[英]How do I make an XML layout for a ListView row where there is a TextView left-aligned and a TextView right-aligned?
基本上,我要查找的是ListView中的行,如下所示:
Title: Harry Potter
Hardcover: Yes
Own: No
Country: United States
有人可以发布这些行之一的XML布局吗? 我的代码似乎无法正确处理。
这就是我的普遍错误,无法正常工作:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content">
<TableLayout
android:id="@+id/tableLayout1"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:stretchColumns="0"
>
<TableRow
android:id="@+id/tableRow1"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
<TextView
android:id="@+id/txtKey"
android:layout_height="fill_parent"
android:layout_gravity="left"
android:textSize="18dip"
android:layout_marginLeft="8dip"
android:textStyle="bold"
android:layout_marginTop="2dp"
android:layout_marginBottom="2dp"
android:text="test"
/>
<TextView
android:id="@+id/txtValue"
android:layout_height="fill_parent"
android:layout_gravity="right"
android:textSize="18dip"
android:layout_marginRight="8dip"
android:layout_marginTop="2dp"
android:layout_marginBottom="2dp"
android:text="test2"
/>
</TableRow>
</TableLayout>
</LinearLayout>
得到它了。
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content">
<TableLayout
android:id="@+id/tableLayout1"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:stretchColumns="0"
>
<TableRow
android:id="@+id/tableRow1"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
<TextView
android:id="@+id/txtKey"
android:text="Some text"
android:textSize="18dip"
android:textStyle="bold"
android:layout_marginLeft="8dip"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="left"
android:layout_weight="1.0"
android:layout_marginTop="2dp"
android:layout_marginBottom="2dp"
/>
<TextView
android:id="@+id/txtValue"
android:text="Some text"
android:textSize="18dip"
android:layout_marginRight="8dip"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="right"
android:layout_weight="1.0"
android:layout_marginTop="2dp"
android:layout_marginBottom="2dp"
/>
</TableRow>
</TableLayout>
</LinearLayout>
res / layout / listitem.xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<TextView
android:id="@+id/textLeft"
android:layout_weight="1"
android:gravity="left"
android:layout_gravity="left"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
<TextView
android:id="@+id/textRight"
android:layout_weight="1"
android:gravity="right"
android:layout_gravity="right"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
</LinearLayout>
然后在您的活动中:
ListView listView = (ListView) findViewById(R.id.list);
listView.setAdapter(new BaseAdapter() {
final String[][] keysAndValues = {
{"key1", "value1"},
{"key2", "value2"},
{"key3", "value3"}
};
@Override
public int getCount() {
return keysAndValues.length;
}
@Override
public String[] getItem(int position) {
return keysAndValues[position];
}
@Override
public long getItemId(int position) {
return position;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
TextView[] foundTextFields;
if(convertView == null) {
convertView = LayoutInflater.from(parent.getContext()).inflate(
R.layout.listitem, parent, false);
foundTextFields = new TextView[] {
(TextView) convertView.findViewById(R.id.textLeft),
(TextView) convertView.findViewById(R.id.textRight)
};
convertView.setTag(foundTextFields);
}
else {
foundTextFields = (TextView[]) convertView.getTag();
}
String[] item = getItem(position);
foundTextFields[0].setText(item[0]);
foundTextFields[1].setText(item[1]);
return convertView;
}
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.