[英]trying to set session variable
if(isset($_SESSION['admin'])) {
echo "<li><b>Admin</b></li>";
}
<?php
session_name('MYSESSION');
session_set_cookie_params(0, '/~cgreenheld/');
session_start();
$conn = blah blah
$query2 = 'Select Type from User WHERE Username = "'.$_SESSION['user'].'" AND Type =\'Admin\'';
$result2 = $conn->query($query2);
if($result2->num_rows==1) {
$_SESSION['admin'] = $result2;
}
?>
嗨,我正在尝试设置此会话变量,但似乎没有设置,我想知道是否有人可以提供帮助。 如果设置了session ['admin'],则应回显admin按钮。 但是我不太确定为什么? (我确实在每个页面上都有会话启动和所有内容,这不是问题,也不是我检查了mysql查询的任何“您没有php标记”问题,并且确实从表中返回了一些东西。请问有什么想法吗?
您的session_start();
应该与页面变量无关的页面顶部。
从文档 :
当调用session_start()或自动启动会话时,PHP将调用打开并读取会话保存处理程序。
编辑评论:
<?php
session_name('MYSESSION');
session_set_cookie_params(0, '/~cgreenheld/');
session_start();
// Moved to start after answer was accepted for better readability
// You had the <?php after this if statement? Was that by mistake?
if(isset($_SESSION['admin']))
{
echo "<li><b>Admin</b></li>";
}
// If you have already started the session in a file above, why do it again here?
$conn = blah blah;
$query2 = 'Select Type from User WHERE Username = "'.$_SESSION['user'].'" AND Type =\'Admin\'';
// Could you echo out the above statement for me, just to
// make sure there aren't any problems with your sessions at this point?
$result2 = $conn->query($query2);
if($result2->num_rows==1)
{
$_SESSION['admin'] = $result2;
// It seems you are trying to assign the database connection object to it here.
// perhaps try simply doing this:
$_SESSION['admin'] = true;
}
?>
从进一步的评论中编辑2:
您实际上必须像这样提取数据-从本教程中摘录可能会帮助您一些更多的事情:
$query = "SELECT name, subject, message FROM contact";
$result = mysql_query($query);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo "Name :{$row['name']} <br>" .
"Subject : {$row['subject']} <br>" .
"Message : {$row['message']} <br><br>";
}
但是,尽管如此,在我们谈论它的同时,最好不要使用旧的mysql_*
函数,而要使用更好的PDO 。
移动session_start();
到页面顶部。 您正在尝试检索未加载的会话。
编辑:尝试回显$_SESSION['admin']
,即使它包含某些内容。 还可以尝试通过添加echo('its working');
调试if($result2->num_rows==1)
代码echo('its working');
或die('its working');
在其中检查$ result2是否正好包含1行,因为当前看来$ result2包含多于1行或根本没有行。
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