[英]How to get all similar named records in mysql
我有一个表,其中包含存储的数据,例如:
product_name | quantity | tert
ASIZ A4 100 FOX | 20| BUYER1
CERVEZA A6 150 FOX | 15| BUYER1
ASIZ A4 150 FOX | 40| BUYER1
CERVEZA A6 11 FOX | 15| BUYER1
QUINTA A6 150 FOX | 15| BUYER2
ASIZ A4 150 FOX | 33 | BUYER2
ASIZ A6 150 FOX | 15| BUYER2
CERVEZA A6 150 FOX | 15| BUYER2
我想检索所有与第一个单词匹配的数据(例如ASIZ )求和的数量并将其显示为:
BUYER1
Asiz - 60 pcs.
Cerveza = 30 pcs.
etc.
BUYER2
Asiz = 48 pcs.
Cerveza = 15 pcs.
等等
目前我正在使用2 while循环:
SELECT DISTINCT product_name
FROM my_table
WHERE buyer_code= '".$bcode."'
GROUP BY product_name
-然后我得到了产品名称
然后
SELECT DISTINCT product_name,tert, SUM(quantity) AS quantity
FROM my_table
WHERE buyer_code ='".$bcode."' AND
prouct_name LIKE '".$first_word_of_product_name."%'
GROUP BY tert
ORDER BY data ASC
我得到正确的总和,但是每次找到相似的命名产品时,它就会列出它们(例如: BUYER1:ASIZ-2次,等等)
表明:
Buyer1
ASIZ - 60
Cerveza - 30
ASIZ - 60
Cerveza - 30
我知道它与product_name有关,但是我应该如何编写sql语句来起作用? 谢谢
SELECT SUBSTRING_INDEX(product_name, '.', 1) product, tert, SUM(quantity) quantity
FROM my_table
GROUP BY product, tert
从第二个SQL中删除tert
,它将按预期工作。
更改为
SELECT DISTINCT product_name,tert, SUM(quantity) AS quantity
FROM my_table
WHERE buyer_code ='".$bcode."'
AND prouct_name LIKE '".$first_word_of_product_name."%'
GROUP BY tert
ORDER BY data ASC
这个
SELECT DISTINCT product_name, SUM(quantity) AS quantity
FROM my_table
WHERE buyer_code ='".$bcode."'
AND prouct_name LIKE '".$first_word_of_product_name."%'
GROUP BY product_name
ORDER BY data ASC
跑
SELECT tert, SUBSTRING_INDEX(product_name,' ',1) as product, sum(quantity) as qty
FROM my_table
GROUP BY tert, product
ORDER BY tert, product
您的结果将按tert排序,因此您可以逐一浏览显示产品和数量,并在每次tert更改时显示tert 。
UPDATE :一个代码示例如何输出数据(未测试):
$tert = null;
foreach($rows as $row){
if($rows['tert'] != $tert){
$tert = $rows['tert'];
echo $tert;
}
echo $row['product'], "-", $row['qty'];
}
$rows
所有提取的行。
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