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java persistence native sql不接受参数

[英]java persistence native sql not accepting parameters

我的疑问是

sql = "SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) 
         FROM MV_MFT_TRANSFER 
        WHERE TRANSFER_INITIATION_TIME > :startDate 
          AND TRANSFER_INITIATION_TIME < :endDate"

Query query = em.createNativeQuery(sql);
query.setParameter("startDate", startDate, TemporalType.DATE);
query.setParameter("endDate", endDate, TemporalType.DATE);
query.getResultList();'

当我运行它时,我收到一个错误

SQLExceptionTHrown: 
<Sep 11, 2012 12:50:46 PM PDT> <Warning> <EclipseLink> <BEA-2005000> <2012-09-11 12:50:46.893--UnitOfWork(1387841584)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.4.1.v20120804-d768c4f): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Missing IN or OUT parameter at index:: 1
Error Code: 17041
Call: SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) FROM MV_MFT_TRANSFER WHERE TRANSFER_INITIATION_TIME > :startDate AND TRANSFER_INITIATION_TIME < :endDate
Query: DataReadQuery(sql="SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) FROM MV_MFT_TRANSFER WHERE TRANSFER_INITIATION_TIME > :startDate AND TRANSFER_INITIATION_TIME < :endDate")> 
***SQLException in init() TRANSFER METRICS BEAN****
Local Exception Stack: 
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.4.1.v20120804-d768c4f): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Missing IN or OUT parameter at index:: 1

以下解决方案应该有效:

sql = "SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) 
         FROM MV_MFT_TRANSFER 
        WHERE TRANSFER_INITIATION_TIME > ?
          AND TRANSFER_INITIATION_TIME < ?"

Query query = em.createNativeQuery(sql);
query.setParameter(1, startDate, TemporalType.DATE);
query.setParameter(2, endDate, TemporalType.DATE);
query.getResultList();

似乎如果你使用位置参数它将起作用。 您无法组合命名参数和本机查询。 以下是一些链接:

http://java.boot.by/scbcd5-guide/ch08s05.html

http://www.wisegeek.com/what-are-native-queries.htm

还有更多,只是谷歌:“只有位置参数绑定可以移植用于本机查询”。

编辑:有类似问题的更多链接:

如何从JDBC查询中获取所有元素

JPA / Hibernate本机查询无法识别参数

这篇文章真有帮助!

http://software-security.sans.org/developer-how-to/fix-sql-injection-in-java-persistence-api-jpa

文章的要点是:

这些是不安全的查询,不要使用它! 字符串连接很糟糕:

List results = entityManager.createQuery("Select order from Orders order where order.id = " + orderId).getResultList();
List results = entityManager.createNativeQuery("Select * from Books where author = " + author).getResultList();
int resultCode = entityManager.createNativeQuery("Delete from Cart where itemId = " + itemId).executeUpdate();

这些都是安全的查询。

/* positional parameter in JPQL */
Query jpqlQuery = entityManager.createQuery("Select order from Orders order where order.id = ?1");
List results = jpqlQuery.setParameter(1, "123-ADB-567-QTWYTFDL").getResultList();

/* named parameter in JPQL */
Query jpqlQuery = entityManager.createQuery("Select emp from Employees emp where emp.incentive > :incentive");
List results = jpqlQuery.setParameter("incentive", new Long(10000)).getResultList();

/* named query in JPQL - Query named "myCart" being "Select c from Cart c where c.itemId = :itemId" */
Query jpqlQuery = entityManager.createNamedQuery("myCart");
List results = jpqlQuery.setParameter("itemId", "item-id-0001").getResultList();

/* Native SQL */
Query sqlQuery = entityManager.createNativeQuery("Select * from Books where author = ?", Book.class);
List results = sqlQuery.setParameter(1, "Charles Dickens").getResultList();

在JPA

当你使用这个:

查询查询= em。 createNativeQuery (sql);

您必须为设置参数设置索引。 请注意,您的查询具有多个参数。

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