如何在执行row_number时不计算0

Question

我正在对某些数据执行row_number() 。

我的问题是我不屈服于考虑0数据。

这是我的数据示例：

+-----------+-----+
| Alex      |   1 |
| Liza      |   2 |
| Harry     |   0 |
| Marge     |  24 |
| Bla       |   0 |
| Something | 234 |
+-----------+-----+

这就是我想要的：

+-----------+--------+------------+
|   name    | number | row_number |
+-----------+--------+------------+
| Harry     |      0 |          0 |
| Bla       |      0 |          0 |
| Something |    234 |          1 |
| Marge     |     24 |          2 |
| Liza      |      2 |          3 |
| Alex      |      1 |          4 |
+-----------+--------+------------+

如您所见，第三列是the row_number()

这是我到目前为止所拥有的：

select name, number, row_number() over (partition by name order by name,number)
from myTable

如何获取上面的查询，以对源数据中的所有0's返回0 ， 而不对row_number序列完全计数0 ？

Answer 1

试试这个SQL小提琴 ：

SELECT name, number, 0 as [row_number]
FROM myTable
WHERE number = 0
UNION ALL
SELECT name, number, row_number() OVER (ORDER BY number DESC)
FROM myTable
WHERE number <> 0

Answer 2

尝试这个：

select name, number,
       (case when number = 0 then 0
             else row_number() over (partition by iszero order by number desc)
        end) as row_number
from (select t.*, (case when number = 0 then 0 else 1 end) as iszero
      from myTable t
     ) t

由于您按数字降序排列，因此如果没有数字为负数，则可以使用以下方法：

select name, number,
       (case when number = 0 then 0
             else row_number() over (order by number desc)
        end) as row_number
from myTable t