[英]How to send an image to a Javascript client using JSON from a Java server
[英]send a variable from java client to php server via Json
我是Java和PHP的初学者,我正在开发一个包含2部分的应用程序:
Android客户端(Java)和PHP服务器。
我尝试了许多可用的教程,并阅读了有关用户所犯的错误,但都未能成功!
这是我正在使用的教程之一:Java文件
package org.postandget;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
public class Main extends Activity {
TextView tv;
String text;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
tv = (TextView)findViewById(R.id.textview);
text = "";
try {
postData();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void postData() throws JSONException{
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/ReceiveLocation.php");
JSONObject json = new JSONObject();
try {
// JSON data:
json.put("name", "Fahmi Rahman");
json.put("position", "sysdev");
JSONArray postjson=new JSONArray();
postjson.put(json);
// Post the data:
httppost.setHeader("json",json.toString());
httppost.getParams().setParameter("jsonpost",postjson);
// Execute HTTP Post Request
System.out.print(json);
HttpResponse response = httpclient.execute(httppost);
// for JSON:
if(response != null)
{
InputStream is = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
text = sb.toString();
}
tv.setText(text);
}catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
}
这是PHP文件
<?php
include('ConnectionFunctions.php');
Connection();
$json = $_POST['jsonpost'];
echo "JSON: \n";
echo "--------------\n";
var_dump($json);
echo "\n\n";
$data = json_decode($json);
echo "Array: \n";
echo "--------------\n";
var_dump($data);
echo "\n\n";
$name = $data->name;
$pos = $data->position;
echo "Result: \n";
echo "--------------\n";
echo "Name : ".$name."\n Position : ".$pos;
?>
这是我运行php时出现的错误
Notice: Undefined index: HTTP_JSON in C:\xampp\htdocs\ReceiveLocation.php on line 5
JSON: -------------- NULL Array: -------------- NULL
Notice: Trying to get property of non-object in C:\xampp\htdocs\ReceiveLocation.php on line 17
Notice: Trying to get property of non-object in C:\xampp\htdocs\ReceiveLocation.php on line 18
Result: -------------- Name : Position :
使用以下方法访问JSON数据:
$json = $_POST['jsonpost'];
您试图访问您的php文件中的无效字段,应该是
$json = $_POST['jsonpost'];
要么
$json = $_REQUEST['jsonpost'];
如果您打算对数据进行数据库处理,请记住还要对来自php文件中错误输入的数据进行消毒。 另外也许您的本地主机路径应该从
HttpPost httppost = new HttpPost("http://127.0.0.1/ReceiveLocation.php");
至
HttpPost httppost = new HttpPost("http://10.0.2.2/ReceiveLocation.php");
希望我能帮上忙。
您的代码有问题,JSON数据仅添加到标头,而不添加到HTTP请求的POST部分。
所以当你输出:
print_r(getallheaders());
$headers = getallheaders();
$json = json_decode($headers['json']);
print_r($json);
您应该看到自己的数据。 我现在没有修复程序,但我正在努力。
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