[英]Return mysqli query result as an array in PHP
我一直在互联网上搜索一段时间,但由于我是MySQLi的新手,我自己无法解决这个问题。 到目前为止这是我的代码。 我想将结果作为数组返回。
function myFunction($u_id, $mysqli){
$userinfo = "SELECT email, name, street, placename FROM users WHERE u_id = ? LIMIT 1";
if($stmt = $mysqli->prepare($userinfo)) {
$stmt->bind_param('i', $u_id);
$stmt->execute();
if(!$stmt->execute()) {
echo $stmt->error.' in query: '.$userinfo;
} else {
//this is what i found somewhere on the internet, and it gives me an array with the right keys but empty values.
$meta = $stmt->result_metadata();
while ($field = $meta->fetch_field()) {
$var = $field->name;
$$var = null;
$parameters[$var] = &$$var;
}
return $parameters;
}
$stmt->close();
}}
希望有人可以帮助我使这些代码工作,或帮助我找到替代方案。
你有没有看过使用fetch_array
http://php.net/manual/en/mysqli-result.fetch-array.php
使用您的代码
function myFunction($u_id, $mysqli){
$userinfo = "SELECT email, name, street, placename FROM users WHERE u_id = ? LIMIT 1";
if($stmt = $mysqli->prepare($userinfo))
{
$stmt->bind_param('i', $u_id);
$stmt->execute();
if(!$stmt->execute())
{
echo $stmt->error.' in query: '.$userinfo;
}
else {
//this is what i found somewhere on the internet, and it gives me an array with the right keys but empty values.
$parameters = array();
while ($row = $stmt->fetch_assoc()) {
$parameters[] = $row;
}
$stmt->close();
return $parameters;
}
$stmt->close();
}
}
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