[英]calling an Action in the Controller through JQuery from the cshtml and returning a value back
我有一个cshtml页面,有3个文本框和3个下拉列表。
我的想法是让用户在第一个问题下拉列表中做出决定(是/否),并根据此答案填充第二个文本框,并启用第二个下拉列表(是/否),并为第三个下拉列表启用相同的过程文本框。
我现在有以下内容: -
<script type="text/javascript">
$(document).ready(function () {
//disable the textboxes
$("#T_FirstQuestion").attr('disabled', true);
$("#T_SecondQuestion").attr('disabled', true);
$("#T_ThirdQuestion").attr('disabled', true);
//and the dropdowns intially
$("#SecondQuestYesNo").attr('disabled', true);
$("#ThirdQuestYesNo").attr('disabled', true);
$("#FirstQuestYesNo").change(function () {
val = $("#FirstQuestYesNo").val();
PostValue(val);
});
function PostValue(val) {
var url = "/Home/DecisionFirstQuest";
$("#T_SecondQuestion").attr('enabled', true);
$.ajax({
type: "POST",
url: url,
data: { value: val }
}).done(function (msg) {
alert("Data Saved: " + msg);
});
}
});
</script>
@using (Html.BeginForm("Decision", "Home", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<table>
<tr>
<td> <font face="Arial" size="2"><b>1</b></font>
</td>
<td>
@Html.TextBox("T_FirstQuestion", ViewData["T_FirstQuestion"], new { @class = "NormalTextBox" })
</td>
<td>
@Html.DropDownList("FirstQuestYesNo", ViewData["FirstQuestYesNoData"] as SelectList, new { @class = "normalDropdowns" })
</td>
</tr>
<tr>
<td> <font face="Arial" size="2"><b>1</b></font>
</td>
<td>
@Html.TextBox("T_SecondQuestion", ViewData["T_SecondQuestion"], new { @class = "NormalTextBox" })
</td>
<td>
@Html.DropDownList("SecondQuestYesNo", ViewData["SecondQuestYesNoData"] as SelectList, new { @class = "normalDropdowns" })
</td>
</tr>
<tr>
<td> <font face="Arial" size="2"><b>1</b></font>
</td>
<td>
@Html.TextBox("T_ThirdQuestion", ViewData["T_ThirdQuestion"], new { @class = "NormalTextBox" })
</td>
<td>
@Html.DropDownList("ThirdQuestYesNo", ViewData["ThirdQuestYesNoData"] as SelectList, new { @class = "normalDropdowns" })
</td>
</tr>
</table>
}
我的控制器如下: -
public ActionResult DecisionFirstQuest(string value)
{
string strMessage = "";
if (value == "Yes")
{
strMessage = "You have chosen YES!";
}
else
{
strMessage = "You have chosen NO!";
}
ViewData["T_SecondQuestion"] = strMessage;
return RedirectToAction("Decision");
}
public ActionResult DecisionSecondQuest(string value)
{
string strMessage = "";
if (value == "Yes")
{
strMessage = "You have chosen YES!";
}
else
{
strMessage = "You have chosen NO!";
}
ViewData["T_ThirdQuestion"] = strMessage;
return RedirectToAction("Decision");
}
public ActionResult Decision()
{
string FirstQuestYesNo = HttpContext.Request["FirstQuestYesNo"];
ViewData["T_FirstQuestion"] = "First Question Text";
var ddlYesNoData = new SelectList(new[]
{
new {ID="",Name="Please Select"},
new {ID="Yes",Name="Yes"},
new{ID="No",Name="No"},
},
"ID", "Name", 1);
if (!String.IsNullOrEmpty(FirstQuestYesNo))
ViewData["FirstQuestYesNoData"] = FirstQuestYesNo;
else
ViewData["FirstQuestYesNoData"] = "Yes";
ViewData["FirstQuestYesNoData"] = ddlYesNoData;
ViewData["SecondQuestYesNoData"] = ddlYesNoData;
ViewData["ThirdQuestYesNoData"] = ddlYesNoData;
return View();
}
我正在设法获得第一个下拉列表的值,并重定向到决策操作,但是我没有填写第二个问题文本框。 此外,我得到一个带有一些HTML代码的弹出窗口,我想避免。
所以基本上我的问题是,如何填写第二个文本框,并在用户选择(是/否)后,填写第三个文本框。
另外,我使用正确的方法还是有更好的方法来使用MVC?
谢谢你的帮助和时间!
------------------- UPDATE ------------------------------ --------------我决定去寻找一个更简单的例子
<script type="text/javascript">
$(document).ready(function () {
$("#YesNo").change(function () {
val = $("#YesNo").val();
var url = "../Home/Decision";
$.post(url, { value: val});
});
});
</script>
@using (Html.BeginForm("Decision", "Home", FormMethod.Post, new { enctype = "multipart/form-data", id="Decision" }))
{
@Html.DropDownList("YesNo", new List<SelectListItem>
{
new SelectListItem{ Text="Select", Value = "" },
new SelectListItem{ Text="Yes", Value = "Yes" },
new SelectListItem{ Text="No", Value = "No" }
})
string FirstQuestText = ViewBag.FirstQuestData;
@Html.TextBox("T_FirstQuestion", FirstQuestText, new { @class = "NormalTextBox" })
}
控制器行动: -
[HttpPost]
public ActionResult Decision(string value)
{
string strMessage = "";
if (value == "Yes")
{
strMessage = "This is the Second Yes Question";
}
else
{
strMessage = "This is the Second No Question";
}
ViewBag.FirstQuestData = strMessage;
return View();
}
现在的问题是我正在正确填充ViewBag.FirstQuestData,但它没有显示在@Html.TextBox中
----------------------------------- JSON UPDATE ------------- -------------------------- cshtml
$("#YesNoQuest1").change(function () {
alert('change');
val = $("#YesNoQuest1").val();
var url = "../Home/Decisions1";
$.getJSON(url, function(data) {
alert(data.message);
});
调节器
[HttpPost]
public JsonResult Decisions1(string value)
{
string strMessage = "";
if (value == "Yes")
{
strMessage = "This is the Second Yes Question";
}
else
{
strMessage = "This is the Second No Question";
}
return Json(new { message = strMessage }, JsonRequestBehavior.AllowGet);
}
尝试返回基于字符串的数据,而不是重定向到Action,如下所示:
[HttpPost]
public ActionResult Decision(string value)
{
string strMessage = "";
if (value == "Yes")
{
strMessage = "This is the Second Yes Question";
}
else
{
strMessage = "This is the Second No Question";
}
ViewBag.FirstQuestData = strMessage;
return Content(strMessage); //No need to return complete View
}
您可以在Ajax帖子调用中收到此消息,如下所示:
$("#YesNo").change(function () {
val = $("#YesNo").val();
var url = "../Home/Decision";
$.post(url, { value: val},function(data){
alert(data);
//Here you can right your logic to manipulate data
});
});
希望这可以帮助:
-------更新使用JSON数据-------------------这是控制器返回Json:
[HttpGet]
public ActionResult YourController()
{
//Do your Logic
return Json(new { message = "Data" }, JsonRequestBehavior.AllowGet);
}
$.getJSON("../YourController", function(data) {
alert(data.foo);
alert(data.baz);
});
如果使用“Json result”将Controller的响应返回给View,请在Ajax设置中将数据类型称为“json”
function PostValue(val) {
var url = "/Home/DecisionFirstQuest";
$("#T_SecondQuestion").attr('enabled', true);
$.ajax({
type: "POST",
url: url,
dataType:'json',
data: { value: val }
}).done(function (msg) {
alert("Data Saved: " + msg);
});
}
并且您可以在“msg”对象中获取结果。
注意:请勿使用getJSON(),因为它会缓存可能导致您的数据与您的存储库不同步的响应。 但你仍然可以在ajax设置中通过settinb cache = FALSE使用它,如下所示:
$ .ajaxSetup({缓存:假});
这行应该在你的ajax调用之前。
谢谢
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