[英]Retrieving data from two tables in Doctrine
我在这里有一个小问题:
$advList = Doctrine::getTable('Advertiser')
->createQuery('a')
->leftJoin('a.PrincCity p')
->leftJoin('a.TourCity t')
->leftJoin('a.Category')
->orderBy('a.new DESC')
->where('a.is_activated = ?', true)
->andWhereNotIn('a.category_id', array(4, 5))
->andWhere('( (t.slug IS NULL AND p.slug = ?) OR t.slug = ?)', array($city_slug, $city_slug))
->addOrderBy('a.created_at DESC');
$this->pager = new sfDoctrinePager('Advertiser', 50);
$this->pager->setQuery($advList);
$this->pager->setPage($request->getParameter('page', 1));
$this->pager->init();
此代码从一个城市获取所有广告客户(在表Advertiser中由ID表示)-现在我有了第二个表Advertiser-City,其中包含id,AdvertiserId和CityID,因此我可以为一个广告商拥有多个城市(例如5个广告客户ID为99的行, CityID)。
问题是我需要从一个城市获取所有广告商,但是上层代码只能与数据库中的一个表一起使用,因此我不知道如何在第二个表中(与其他城市一起)进行搜索。
我不确定我是否能理解您的问题,但是我认为,如果您已经明确定义了nm Advertiser-city关系:
Advertiser:
...
relations:
Cities: { class: City, refClass: AdvertiserCity, local: advertiser_id, foreign: city_id }
AdvertiserCity:
columns:
advertiser_id: { type: integer,...}
city_id: { type: integer,....}
...
relations:
City: { local: city_id, foreign: id, foreignAlias: AdvertiserCities }
Advertiser: { local: advertiser_id, foreign: id, foreignAlias: AdvertiserCities }
然后,您的查询可以像这样:
$advList = Doctrine::getTable('Advertiser')
->createQuery('a')
->innerJoin('a.Cities c')
...
->addWhere('c.id = ?',$city_id)
...;
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