[英]Prevent Javascript from executing in Safari
以下平滑滚动脚本使我在Safari中的导航混乱(锚标记不再起作用)。 我是Javascript新手,有人可以告诉我如何在此脚本中检测Safari并阻止它在检测到Safari时执行吗? 非常感谢!
// JavaScript Document
$(document).ready(function() {
function filterPath(string) {
return string
.replace(/^\//,'')
.replace(/(index|default).[a-zA-Z]{3,4}$/,'')
.replace(/\/$/,'');
}
var locationPath = filterPath(location.pathname);
var scrollElem = scrollableElement('html', 'body');
$('a[href*=#]').each(function() {
var thisPath = filterPath(this.pathname) || locationPath;
if ( locationPath == thisPath
&& (location.hostname == this.hostname || !this.hostname)
&& this.hash.replace(/#/,'') ) {
var $target = $(this.hash), target = this.hash;
if (target) {
var targetOffset = $target.offset().top;
$(this).click(function(event) {
event.preventDefault();
$(scrollElem).animate({scrollTop: targetOffset}, 1300, function() { // scroll speed
location.hash = target;
});
});
}
}
});
// use the first element that is "scrollable"
function scrollableElement(els) {
for (var i = 0, argLength = arguments.length; i <argLength; i++) {
var el = arguments[i],
$scrollElement = $(el);
if ($scrollElement.scrollTop()> 0) {
return el;
} else {
$scrollElement.scrollTop(1);
var isScrollable = $scrollElement.scrollTop()> 0;
$scrollElement.scrollTop(0);
if (isScrollable) {
return el;
}
}
}
return [];
}
});
请参阅: http : //api.jquery.com/jQuery.browser/ ,以检测浏览器并仅在非Safari浏览器时执行脚本
var isSafari = navigator.userAgent.indexOf("Safari") > -1 && navigator.userAgent.indexOf("Chrome") == -1;
if(!isSafari){
// do your magic
}
也许这:
$(document).ready(function()
{
if (navigator.appVersion.match(/WebKit/) && !navigator.vendor.match(/Google/))
{
return;
}
//rest of your code
});
如果您在$(document).ready回调之外有任何代码,则可以通过在脚本顶部写入以下错误来杀死该脚本:
if (navigator.appVersion.match(/WebKit/) && !navigator.vendor.match(/Google/))
{
throw new Error('Safari not supported');
}
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