php，mysql，“在while语句之后

Question

我该如何写一个条件，使得如果找不到该行就可以做什么？

我的密码

$resultt = mysql_query("SELECT * FROM objednavky WHERE kdo = '$kdo' and kdy = '$the_rday'");
                        while ($roww = mysql_fetch_array($resultt)) {

                            echo "<form method='post' action=''>
                                  <label for='obb1'>Menu #1&emsp;</label>
                                  <input type='text' name='obb1' value='$roww[3]' size='4'><br>
                                  <label for='obb1'>Menu #2&emsp;</label>
                                  <input type='text' name='obb2' value='' size='4'><br>
                                  <label for='obb1'>Menu #3&emsp;</label>
                                  <input type='text' name='obb3' value='' size='4'><br>
                                  <input type='submit' value='objednat'></form>";


                        }

我想继续这样

   ...} else {
echo " no match ";
}

非常感谢您的帮助。

Answer 1

在这种情况下，您可以使用mysql_num_rows()

$resultt = mysql_query("SELECT * FROM objednavky WHERE kdo = '$kdo' and kdy = '$the_rday'");


   if(mysql_num_rows($resultt)<1){
   echo "not found";
   }else{

     while(...)

       }

Answer 2

这可以通过mysql_num_rows（）完成

 if($resultt && mysql_num_rows($resultt)>1){


             while ($roww = mysql_fetch_array($resultt)) {

                        echo "<form method='post' action=''>
                              <label for='obb1'>Menu #1&emsp;</label>
                              <input type='text' name='obb1' value='$roww[3]' size='4'><br>
                              <label for='obb1'>Menu #2&emsp;</label>
                              <input type='text' name='obb2' value='' size='4'><br>
                              <label for='obb1'>Menu #3&emsp;</label>
                              <input type='text' name='obb3' value='' size='4'><br>
                              <input type='submit' value='objednat'></form>";


                    }}  else {
                         echo " no match ";
                       }

但是不建议使用mysql_*函数，请改用pdo或mysqli