SQL Server查询以XML形式获取所有表的列名

Question

在我的数据库中，我打算为数据库中的所有表获取-[TableName]作为表的第一列，并将该表的所有列以“，”（逗号后跟空格-定界符）作为第二列。

Table A | ColumnA1, ColumnA2, ColumnA3  
Table B | ColumnB1, ColumnB2, ColumnB3
......................................

并将其检索为XML

<TableList>  
<TableName>TableA</TableName> <Columns> ColumnA1, ColumnA2, ColumnA3</Columns>  
<TableName>TableB</TableName> <Columns> ColumnB1, ColumnB2, ColumnB3</Columns>  
</TableList>

应该如何编写SQL查询？

Answer 1

这将为您提供所需的XML。

select T.name as TableName,
       (
         select ', '+C.name
         from sys.columns as C
         where C.object_id = T.object_id
         order by C.column_id
         for xml path(''), type
       ).value('substring((./text())[1], 3)', 'varchar(max)') as Columns
from sys.tables as T
order by T.name
for xml path(''), root('TableList')

但是我认为这将返回易于处理的XML。

select T.name as TableName,
       (
         select ', '+C.name
         from sys.columns as C
         where C.object_id = T.object_id
         order by C.column_id
         for xml path(''), type
       ).value('substring((./text())[1], 3)', 'varchar(max)') as Columns
from sys.tables as T
order by T.name
for xml path('Table'), root('TableList')

也许像这样。

select T.name as TableName,
       (
         select C.name as ColumnName
         from sys.columns as C
         where C.object_id = T.object_id
         order by C.column_id
         for xml path(''), type
       ) as Columns
from sys.tables as T
order by T.name
for xml path('Table'), root('TableList')

Answer 2

你可以试试这个

   select isc.TABLE_NAME,stuff((
    SELECT ',' + cast(column_name as varchar(20))
    FROM INFORMATION_SCHEMA.COLUMNS where TABLE_NAME =isc.TABLE_NAME 
     group by TABLE_NAME,COLUMN_NAME
    FOR XML PATH('') 
    ),1,1,'')  as column_name from INFORMATION_SCHEMA.COLUMNS isc
     group by TABLE_NAME