[英]Program debugging
程序输出应如下所示:
Enter an even number: 23
The number is not a positive even number.
Enter an even number: -6
The number is not a positive even number.
Enter an even number: 4
20 20.25 20.50 20.75 21
The sum is 102.5
程序无法正常运行。 识别出奇/偶数,但是递增变量(20 + 1 /(输入的偶数))的循环无法正常进行。
#include <iostream>
int main(int argc, char *argv[])
{
float val, sum, incr;
int num;
cout << "Enter an even number: ";
cin >> num;
if (num % 2 != 0)
cout << "The number " << num << " is not a positive even number." << endl;
else
cout << num << " is even!" << endl << endl;
incr = 1 / num;
for (val = 20.0F; val <= 21.0; val += incr)
{
cout << val;
sum += val;
}
cout << "The sum is " << sum << endl;
return 0;
}
如果分割一个整数1
彼此之间num
的结果是一个整数,如克里斯说是0。
你应该做:
incr = 1.0F / (float)num;
对于错误的引入值退出,您应该从main返回
#include <iostream>
int main() {
float val, sum, incr;
int num;
cout << "Enter an even number: ";
cin >> num;
if (num < 0 || num % 2 != 0){
cout << "The number " << num << " is not a positive even number." << endl;
return -1;
}
else {
cout << num << " is even!" << endl << endl;
}
incr = 1.0 / num;
for (val = 20.0F; val <= 21.0; val += incr) {
cout << val << " ";
sum += val;
}
cout << "The sum is " << sum << endl;
return 0;
}
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