[英]Pass array from controller to view - Codeigniter
我尝试在控制器中打印数组,然后将其传递给视图,这是输出
Array ( [annunci] => Array ( [0] => stdClass Object ( [EmailDatore] => you@welcom.it [Nome] => asdasd [Cognome] => asdas [IdAnnuncio] => 9 [Titolo] => sfsdfdsfshrea [Testo] => agrefdgdagdfg [Categoria] => [Sede] => [TipoContratto] => [Add_Date] => [Drop_Date] => )
[1] => stdClass Object ( [EmailDatore] => you@welcom.it [Nome] => asdasd [Cognome] => asdas [IdAnnuncio] => 10 [Titolo] => fafa [Testo] => fafaerea asdasdas dafasfd [Categoria] => [Sede] => [TipoContratto] => [Add_Date] => [Drop_Date] => ) ) )
我在maincontroller中从这个方法中获取数组
public function get_annunci(){
$query=$this->user_model->annunci($this->email);
print_r($query);
}
我想将此数组传递给视图,然后读取数据。 所以我像这样重写我的方法
public function get_annunci(){
$query=$this->user_model->annunci($this->email);
$this->load->view('main_view',$query);
}
在主视图中我有这个
<div class="tab-pane active" id="annunci">
<ul>
<?php
print_r($annunci);
?>
</ul>
</div>
这是我的错误
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: annunci
Filename: views/tab_annunci_view.php
Line Number: 4
这是因为您尚未定义$ annunci并使其可用于视图。 您需要先将其加载到视图中
调节器
$data['id'] = $yourArray;
$this->load->view('your_view_file', $data);
视图
<?php print_r($id); ?> //prints $yourArray
public function index()
{
$data=$this->model->viewBlog();
$this->load->view('blog/index',['data'=>$data]);
}
我希望这是有效的。 如果你处理n个记录使用这个方法。
(将$query ['annunci']
更改$query
$query ['annunci']
)确定, $query
已经是一个数组,然后只需将视图文件更改为'tab_annunci_view'
所以:
public function get_annunci(){
$query=$this->user_model->annunci($this->email);
$this->load->view('tab_annunci_view',$query);
}
public function get_annunci(){
$query['annunci']=$this->user_model->annunci($this->email);
$this->load->view('main_view',$query);
}
你正在传递数组,但你没有将annunci作为变量传递。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.