[英]How to write sql query for this:
mysql> select * from table3 order by id;
+------+-------+
| id | value |
+------+-------+
| 1 | a |
| 1 | b |
| 1 | c |
| 1 | d |
| 2 | a |
| 2 | b |
| 3 | a |
| 3 | b |
| 3 | c |
| 4 | a |
| 4 | b |
+------+-------+
我想选择所有没有值'c'的ID 。
不能通过以下查询简单地工作:
mysql> select distinct id from table3 where value <> 'c';
+------+
| id |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
我所需要的只是2和4的回报。
感谢您的关注!
这将为您工作
select distinct id from table3 where
id not in ( select id from table3 where value = 'c')
select distinct id
from table3 t
where not exists
(select 1 from table3 where value = 'c' and id = t.id)
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