如何从iPhone中的UIWebView获取触摸位置的纬度和经度值？

Question

我正在使用iPhone应用程序，使用UIWebView加载Google Map地址，并且可以正常工作。 然后，我尝试从UIWebView获取触摸位置的latitude和longitude值，但我不知道如何执行此操作？ 是否有可能做到这一点？ 请帮我

提前致谢

我尝试了这个：

    webView=[[UIWebView alloc]initWithFrame:CGRectMake(0, 40, 320,376)];
    webView.delegate=self;
    webView.scalesPageToFit=YES;
    NSLog(@"URL:%@",[user valueForKey:@"google_Address"]);
    NSString *googleMapsURLString = [NSString stringWithFormat:@"http://maps.google.com/?saddr=37.785834,-122.406417&output=embed"];
    NSURL *url=[NSURL URLWithString:googleMapsURLString];
    NSURLRequest *requestObj=[NSURLRequest requestWithURL:url];
    [webView loadRequest:requestObj];
    [self.view addSubview:webView];  

Answer 1

我为您的触摸事件坐标找到了解决方案，但是您将不得不使用MKmapView，我将粘贴以下代码

在.h中

 #import <MapKit/MapKit.h> //import this in your project

 //define the objects;
 MKMapView *mapView;
 CLLocationCoordinate2D coordinate;

不要忘记在项目中添加MapKit.framework

在.m中

- (void)viewDidLoad
 {

    mapView = [[MKMapView alloc] initWithFrame:self.view.bounds];//Release it in dealloc
    mapView.delegate=self;

    [self.view addSubview:mapView]; 
    [self displayRegion];

    UITapGestureRecognizer *tgr = [[UITapGestureRecognizer alloc]initWithTarget:self      
    action:@selector(handleGesture:)];   
    tgr.numberOfTapsRequired = 1;
    [mapView addGestureRecognizer:tgr];
    [tgr release];

    [super viewDidLoad];
    // Do any additional setup after loading the view from its nib.
   }

    - (void)handleGesture:(UIGestureRecognizer *)gestureRecognizer
     {
         if (gestureRecognizer.state != UIGestureRecognizerStateEnded)
          return;

         CGPoint touchPoint = [gestureRecognizer locationInView:mapView];
         coordinate = [mapView convertPoint:touchPoint toCoordinateFromView:mapView];

          NSLog(@"latitude  %f longitude %f",coordinate.latitude,coordinate.longitude);


       }


       -(void)displayRegion
         {
           MKCoordinateRegion region;
           MKCoordinateSpan span;
           span.latitudeDelta=0.2;
           span.longitudeDelta=0.2;

           CLLocationCoordinate2D location;

           location.latitude = 22.569722 ;
           location.longitude = 88.369722;


            region.span=span;
            region.center=location;

            [mapView setRegion:region animated:TRUE];
            [mapView regionThatFits:region];
          }

我现在测试了此代码，它为我提供了正确的值，还有其他事情总是尝试在设备上而不是模拟器上进行测试。 尝试并回答您的结果，我想现在应该可以解决

Answer 2

根据我上面的评论，如果您将使用MapKit，则可以使用以下代码获取触摸位置的纬度/经度

- (UIView *)hitTest:(CGPoint)point withEvent:(UIEvent *)event{
CLLocationCoordinate2D coord= [MyMapView convertPoint:point toCoordinateFromView:MyMapView];
NSLog(@"latitude  %f longitude %f",coord.latitude,coord.longitude);


return [super hitTest:point withEvent:event];

}