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具有内部联接的PHP数组选择

[英]PHP Array Select with inner join

当我在数据库中执行sql查询时,我有一个内部联接在按我想要的方式工作。

SELECT debate.date, school1.name, school2.name
FROM debate
INNER JOIN schools as school1
ON debate.homeid=school1.id
INNER JOIN schools as school2
ON debate.awayid=school2.id

退货

date        name        name
19-01-2013  st Peters   St Simons

当我尝试使用php进行此操作时。 我使用相同的select语句并在下面添加。

foreach ($result as $row)
{
  $debates[] = array(
    'date' => $row['date'],
    'awayschool' => $row['name'],
    'homeschool' => $row['name'],
  );
}


<table>
<tr>
<td><?php echo $debate['date']; ?></td>
<td><?php echo $debate['name']; ?></td>
<td><?php echo $debate['name']; ?></td>
</tr>
</table>

哪个返回

date        name        name
19-01-2013  st Peters   st Peters

但是我希望它返回。

date        name        name
19-01-2013  st Peters   St Simons

在我的阵列中,我尝试了几种不同的方法,例如更换

'awayschool' => $row['name'],

'awayschool' => $row['school1.name'],

但执行此操作时出现错误,提示未定义索引。

我在这里做错了什么?

这里的问题是,school1.name和school2.name都(在php中)都名为$ row ['name'],您可以使用AS来获取其中的一个来重命名它

SELECT debate.date, school1.name, school2.name AS name2
FROM debate
INNER JOIN schools as school1
ON debate.homeid=school1.id
INNER JOIN schools as school2
ON debate.awayid=school2.id

然后将您的foreach循环更改为此

foreach ($result as $row)
{
  $debates[] = array(
    'date' => $row['date'],
    'awayschool' => $row['name'],
    'homeschool' => $row['name2'],
  );
}

像这样修改您的查询

SELECT debate.date, school1.name "School1Name", school2.name "School2Name"
FROM debate
INNER JOIN schools as school1
ON debate.homeid=school1.id
INNER JOIN schools as school2
ON debate.awayid=school2.id;

然后:

foreach ($result as $row)
{
  $debates[] = array(
    'date' => $row['date'],
    'awayschool' => $row['School1Name'],
    'homeschool' => $row['School2Name'],
  );
}

只需为它们使用别名即可,例如school1.name AS SCHLNAME1, school2.name AS SCHLNAME2那么这些索引将在您的数组中可用,然后将

'awayschool' => $row['SCHLNAME1'],
'awayschool' => $row['SCHLNAME2']

尝试更改以下内容

<td><?php echo $debate['date']; ?></td>
<td><?php echo $debate['name']; ?></td>
<td><?php echo $debate['name']; ?></td>

对此

 <td><?php echo $debate['date']; ?></td>
 <td><?php echo $debate['awayschool']; ?></td>
 <td><?php echo $debate['homeschool']; ?></td>

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