如何从iPhone的NSString中删除某些字符？

Question

NSString *Address = [placemark.addressDictionary objectForKey:@"FormattedAddressLines"];
NSLog(@"Address:%@", Address);
Address: ("Hooker Alley","San Francisco, CA 94108",USA)

我想从地址字符串中删除一些字符，例如Hooker Alley，San Francisco，CA 94108，USA。 如何删除这样的？ 请帮我

提前致谢

我尝试了这个：

NSString *removeCharacter = [Address stringByReplacingOccurrencesOfString:@"(" withString:@""];

但是错误出现在First throw调用堆栈中：

错误消息是，

-[__NSArrayM stringByReplacingOccurrencesOfString:withString:]: unrecognized selector sent to instance 0x81afd00 

Answer 1

尝试这个，

NSArray *addressArray = [placemark.addressDictionary objectForKey:@"FormattedAddressLines"];
NSString *address = [addressArray componentsJoinedByString:@", "];
NSLog(@"Address:%@", address);

在您的情况下， [placemark.addressDictionary objectForKey:@"FormattedAddressLines"]返回一个数组，而不是单个字符串。 您可以尝试将这些数组组件作为单个字符串连接，如上所示。 另外，您也可以检查

id object = [placemark.addressDictionary objectForKey:@"FormattedAddressLines"];
if([object isKindOfClass[NSArray class]]) {
  //handle as above
} else if([object isKindOfClass[NSString class]]) {
  //use your code
}

Answer 2

您可以删除：-

 NSString *s = @"$$$hgh$g%k&fg$$tw/-tg";
    NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"-/:;()$&@\".,?!\'[]{}#%^*+=_|~<>€£¥•."];
    s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @""];

    NSLog(@"String is: %@", s);

Answer 3

使用isKindOfClass检查addressDictionary objectForKey提供的输出是这样的：

if([[placemark.addressDictionary objectForKey:@"FormattedAddressLines"] isKindOfClass[NSArray class]])
{

  NSArray *address=[placemark.addressDictionary objectForKey:@"FormattedAddressLines"];
  NSLog(@"Address:%@",Address);
  NSString *str = [address componentsJoinedByString: @","]
  NSLog(@"str:%@",str);
}

Answer 4

尝试一次...。它将为您提供帮助

 NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [NSCharacterSet characterSetWithCharactersInString:@"1234567890"];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", resultString);

Answer 5

    NSArray *Address=[placemark.addressDictionary objectForKey:@"FormattedAddressLines"];
     NSLog(@"Address:%@",Address);

     NSMutableString *myString = [[NSMutableString alloc]init];

    for(int i = 0 ; i < [Address count] ; i++){
    [myString appendString:[Address objectAtIndex:i]];


    if (i < [Address count]  ){
    [myString appendString:@","];
       }
 }

NSLog(@"%@",myString);