[英]How to implement Custom XML Serialization in C#
下面是我的XML文件。
<Employee>
<FirstName>#{FirstName}#</FirstName>
<LastName>#{LastName}#</LastName>
<DOB>#{DOB}#</DOB>
<Address>#{Address}#</Address>
<Transcation>
<Month>#{Month}#</Month>
<Amount>#{Amount}#</Amount>
</Transcation>
<Transcation>
<Month>#{Month}#</Month>
<Amount>#{Amount}#</Amount>
</Transcation>
<Transcation>
<Month>#{Month}#</Month>
<Amount>#{Amount}#</Amount>
</Transcation>
<Transcation>
<Month>#{Month}#</Month>
<Amount>#{Amount}#</Amount>
</Transcation>
我的可序列化类是
[XmlRoot("Employee"), Serializable]
public class Employee
{
[XmlAnyElement]
public List<XmlElement> EmployeeDetails { get; set; }
}
但是我想得到这样的东西
在我的EmployeeDetails中,我应该只序列化FirstName,LastName,DOB,Address .....,并且应该在包含Month和Amount作为serialiazable元素的单独类中获取事务处理列表。
像这样的东西
[XmlRoot("Employee"), Serializable]
public class Employee
{
[XmlAnyElement]
public List<XmlElement> EmployeeDetails { get; set; }
[XmlElement("Transcation")]
public List<Transcation> Transcations { get; set; }
}
public class Transcation
{
[XmlElement("Month")]
public string Month{ get; set; }
[XmlElement("Amount")]
public string Amount{ get; set; }
}
我怎样才能做到这一点 ?
假设您无法修改XML,则您的类应如下所示。 可以使用XmlAnyElement,但是您可能需要将其设置为对象数组。 因此,您的代码应如下所示:
[XmlRoot("Employee"), Serializable]
public class Employee
{
[XmlAnyElement]
public XmlElement [] EmployeeDetails { get; set; }
[XmlElement("Transcation")]
public List<Transaction> Transcations { get; set; }
}
要反序列化,请执行以下操作:
private void DeserializeObject(string filename)
{
XmlAnyElementAttribute myAnyElement = new XmlAnyElementAttribute();
XmlAttributeOverrides xOverride = new XmlAttributeOverrides();
XmlAttributes xAtts = new XmlAttributes();
xAtts.XmlAnyElements.Add(myAnyElement);
xOverride.Add(typeof(Employee), "EmployeeDetails", xAtts);
XmlSerializer ser = new XmlSerializer(typeof(Employee), xOverride);
FileStream fs = new FileStream(filename, FileMode.Open);
var g = (Employee)ser.Deserialize(fs);
fs.Close();
Console.WriteLine(g.EmployeeDetails.Length);
foreach (XmlElement xelement in g.EmployeeDetails)
{
Console.WriteLine(xelement.Name + ": " + xelement.InnerXml);
}
}
我建议改为指定属性,这将使查找特定值更加容易。 但这取决于您对XML模式的了解。
[XmlRoot(ElementName="Employee")]
public class Employee
{
[XmlElement(ElementName="FirstName")]
public string FirstName {get;set;}
[XmlElement(ElementName="LastName")]
public string LastName {get;set;}
[XmlElement(ElementName="DOB")]
public DateTime DOB {get;set;}
[XmlElement(ElementName="Address")]
public string Address {get;set;}
[XmlElement(ElementName="Transaction")]
public List<Transaction> Transaction {get;set;}
}
[XmlRoot(ElementName="Transaction")]
public class Transaction
{
[XmlElement(ElementName="Month")]
public int Month {get;set;}
[XmlElement(ElementName="Amount")]
public int Amount {get;set;}
}
如果要完全控制XML的外观,可以创建自己的XMLDocument并手动添加节点/元素。 需要做更多的工作,但是您可以精确地调整XML的外观。
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