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MySQL sum列并将其与给定值进行比较

[英]MySQL sum column and compare it to a given value

我需要从DB显示一组可用房间的结果,其条件是:

  1. alm_num = 1
  2. alm_date在2012年11月26日至29日之间
  3. 和sum_num>或= 3

然后我像这样编写mySQL:

select sum(villas_allotment.alm_num) as sum_num, 
villas_allotment.alm_id as aid, villas_db.v_name as vname  
from villas_allotment 
inner join villas_db on villas_allotment.alm_vid=villas_db.v_id 
where alm_num='1' 
and alm_date between '2012-11-26' and '2012-11-29' 
and alm_vid='3' 
and sum_num>='3'

但我有:

#1054 - Unknown column 'sum_num' in 'where clause'

那么你们可以建议我如何从这个错误中生存下来。 问候,

您需要在聚合列上使用HAVING条件:

select
    sum(villas_allotment.alm_num) as sum_num, 
    villas_allotment.alm_id as aid,
    villas_db.v_name as vname  
from villas_allotment 
inner join villas_db on villas_allotment.alm_vid = villas_db.v_id 
where alm_num = '1' 
and alm_date between '2012-11-26' and '2012-11-29' 
and alm_vid = '3' 
group by villas_allotment.alm_id, villas_db.v_name
having sum(villas_allotment.alm_num) >= 3

您还需要在非聚合列上使用group by子句,我已为您添加了这些列。

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