[英]select distinct column field and total sum for it in mysql
我有下表:
topic_id(unique) forum_id forum_views
1002 1885 5
1003 1893 2
1004 1885 3
1005 1892 6
我如何获得这样的输出:(唯一的forum_id和上表中的总论坛视图)
forum_id forum_views
1885 8
1893 2
1892 6
任何帮助。
这就是我正在尝试的:
从table_name中选择不同的forum_id,sum(topic_views)
select forum_id,
sum(forum_views) as forum_views
from jforum_topics
group by forum_id
使用此查询select forum_id, sum(distinct forum_views) from table group by forum_id;
在此查询中, sum不同将执行不同值的总和并按所需列进行分组。
如果您想要所有值的总和,而与不同性sum(forum_views)
则只需使用sum(forum_views)
。
select forum_id, sum(forum_views) as sum from table_name group by forum_id
您只需要GROUP BY
即可指定您希望SUM
应用于哪些行;
select forum_id, sum(topic_views) from jforum_topics
group by forum_id
order by forum_id
尝试这个:
select forum_id, sum(topic_views)
from jforum_topics
group by forum_id
select forum_id, sum(topic_views) from jforum_topics group by forum_id
试试这个,它将总结您对forum_id的forum_views。
SELECT forum_id
, SUM(forum_views)
FROM TABLE_NAME
GROUP BY forum_id
ORDER BY 1
这将是
select id2,sum(id3) from supportContacts group by id2
看到这个SQL小提琴http://sqlfiddle.com/#!2/7b9e7/3
您也可以尝试以下方法:
select distinct forum_id, sum(topic_views)
from jforum_topics
group by forum_id
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