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来自多个表的mysql_num_rows

[英]mysql_num_rows from multiple tables

我想计算5个表格中的字段数量并显示结果。 我目前只在一张桌子上做

    $variable = mysql_num_rows(mysql_query("SELECT id FROM table1"));

什么是最有效的办法,包括和计算所有idtable2table3table4table5

谢谢

使用UNION ALL组合所有表上的SELECT查询,以获取所有表中ID的总数。 请改用UNION从所有表中获取distinct ID的总数。

$variable = mysql_num_rows(mysql_query("
    "SELECT id FROM table1 " .
    "UNION ALL " .
    "SELECT id FROM table2 " .
    "UNION ALL " .
    "SELECT id FROM table3 " .
    "UNION ALL " .
    "SELECT id FROM table4 " .
    "UNION ALL " .
    "SELECT id FROM table5"));

不要从数据库中获取所有行,只需获取id的数量即可。 让MySQL代替PHP计数。

    $variable1 = mysql_query("SELECT COUNT(id) FROM table1");
    $variable2 = mysql_query("SELECT COUNT(id) FROM table2");
    $variable3 = mysql_query("SELECT COUNT(id) FROM table3");
    $variable4 = mysql_query("SELECT COUNT(id) FROM table4");
    $variable5 = mysql_query("SELECT COUNT(id) FROM table5");

    $variable = $variable1 + $variable2 + $variable3 + $variable4 +$variable5;

不要创建UNION或JOIN,如果您只需要计数,这是一项繁重的工作。

SELECT count(t1.id)+count(t2.id)+count(t3.id)+count(t4.id)+count(t5.id) from table1 as t1, table2 as t2, table3 as t3, table4 as t4, table5 as t5

SELECT COUNT(id) FROM table2

等等

尝试这样的联合语法:

$variable = mysql_num_rows(mysql_query("
SELECT * FROM(
  SELECT id FROM table1
  UNION
  SELECT id FROM table2
  UNION
  SELECT id FROM table3
  UNION
  SELECT id FROM table4
  UNION
  SELECT id FROM table5
)unionNum
"));

完成,祝你好运

第一种方法:

$query = mysql_query("
    select * from(
        SELECT id FROM table1
        union
        SELECT id FROM table2
        union
        SELECT id FROM table3
        union
        SELECT id FROM table4
    )
");
while ($row = mysql_fetch_assoc($query)) {
    //some operations
}
$variable = mysql_num_rows($query);

第二种方法:

$query = mysql_query("
    select count(*) cnt from(
        SELECT id FROM table1
        union
        SELECT id FROM table2
        union
        SELECT id FROM table3
        union
        SELECT id FROM table4
    )
");

while ($row = mysql_fetch_assoc($query)) {
    $variable = $query['cnt'];
}

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