MySQL-通过返回nil从GROUP BY排名COUNT

Question

我正在尝试遵循以下示例： MySQL-按count（）和GROUP BY进行排名，但我的rank列始终返回nil。

这是我的查询：

SELECT 
  @rownum := @rownum+1 AS rank,
  q.id, 
  q.Name, 
  q.count 
FROM
(SELECT
    Accounts.id,
    Accounts.Name,
    COUNT(Accounts.Name) AS count
FROM
    player_to_team_histories
        INNER JOIN
    team_histories ON team_histories.id = player_to_team_histories.team_history_id
        INNER JOIN
    teams ON teams.id = team_histories.team_id
        INNER JOIN
    accounts ON accounts.id = teams.account_id
WHERE
    accounts.AccountTypeId = 1 AND player_id IN (SELECT 
        player_id
    FROM
        player_to_team_histories
    WHERE
        player_to_team_histories.not_valid IS NULL AND team_history_id = (SELECT 
            team_history_id
        FROM
            player_to_team_histories
                INNER JOIN
            team_histories ON team_histories.id = player_to_team_histories.team_history_id
        WHERE
            player_to_team_histories.id = 574651))
GROUP BY Accounts.Name
ORDER BY count DESC)q

除rank之外的所有列均按预期返回，并且rank对每一行返回null 。

Answer 1

您必须先将rownum初始化为0，然后才能开始递增它，方法是

SET @rownum := 0; 

在查询之前，或在您的第一个FROM后面通过单独的SELECT子句：

SELECT ...
FROM
(SELECT @rownum := 0 ) counter, 
(SELECT
 ... )