[英]Templates and g++ 4.7
我有这个代码
namespace MSL{
template <typename T> class TListNode;
template <typename T> class TList;
...
和
template <typename T>
int TList<T>::add(T v) {
TListNode<T> *pn;
pn = new TListNode<T>;
...
和
class TMergeNode {
public:
inline TMergeNode(int cluster1=-1, int cluster2=-1, TCMData mergeVal=0);
inline TMergeNode(TMergeNode &b); // copy constructor
...
使用旧版本的g ++编译就可以了,但是现在使用4.7版,我得到以下错误:
./msl/MSL_List_Template.h: In instantiation of ‘int MSL::TList<T>::add(T) [with T = TMergeNode]’:
clustermerges.cpp:282:33: required from here
./msl/MSL_List_Template.h:616:23: error: no matching function for call to ‘TMergeNode::TMergeNode(TMergeNode)’
./msl/MSL_List_Template.h:616:23: note: candidates are:
In file included from main.cpp:78:0:
clustermerges.cpp:70:8: note: TMergeNode::TMergeNode(TMergeNode&)
clustermerges.cpp:70:8: note: no known conversion for argument 1 from ‘TMergeNode’ to ‘TMergeNode&’
clustermerges.cpp:68:8: note: TMergeNode::TMergeNode(int, int, MSL::TCMData)
clustermerges.cpp:68:8: note: no known conversion for argument 1 from ‘TMergeNode’ to ‘int’
任何想法将不胜感激
在您的代码中,您尝试将临时绑定到非const引用。 这是不允许的。
复制构造函数的正确签名为:
class TMergeNode {
public:
inline TMergeNode(const TMergeNode &b); // copy constructor
// ^^^^^
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