[英]Tricky SQL Join Query
我有两个表,一个名为StudentCerts,包含一个电子邮件(主键)和一个证书,另一个名为CertReqs,包含证书和课程。 表的一部分可能如下:
StudentCerts: CertReqs:
Email Certificate Certificate Course
This@that.com Programmer Programmer CS 101
This@that.com English Programmer CS 202
A@B.com Econ Programmer CS 303
john@smith.com Programmer English ENG 101
English ENG 102
Econ ECON 102
Econ ECON 304
Art Art 101
Art Art 102
Journalism J 101
Journalism J 202
我想要做的是获得特定学生不属于的所有证书。 例如,This@that.com注册了程序员和英语证书。我想得到一个SQL语句,它将返回CertReqs中特定学生未注册的所有证书。所以对于这个例子它应该归还经济,艺术和新闻。 我一直在努力争取这个,所以任何帮助将不胜感激!
SELECT cr.Certificate FROM CertReqs cr
WHERE cr.Certificate NOT IN (
SELECT sc.Certificate FROM StudentCerts sc
WHERE sc.Email = 'This@that.com'
);
该查询几乎可以作为要求:“我想要所有CertReqs,学生不在其中”。
游戏稍晚,但简单的LEFT JOIN
可以很好地解决这个问题:
SELECT DISTINCT cr.Certificate
FROM CertReqs cr
LEFT JOIN StudentCerts sc ON cr.Certificate = sc.Certificate AND sc.Email = 'This@that.com'
WHERE sc.Email IS NULL
这将列出所有缺少某个证书的学生
SELECT DISTINCT x.*
FROM
(
SELECT a.Email, b.Certificate
FROM (SELECT DISTINCT Email FROM StudentCerts) a
CROSS JOIN
(SELECT DISTINCT Certificate FROM CertReqs) b
) x LEFT JOIN studentCerts y
ON x.Email = y.Email AND
x.Certificate = y.Certificate
WHERE y.Email IS NULL
ORDER BY x.EMAIL
如果你想要特定的电子邮件,那么你只需要添加额外的条件
SELECT DISTINCT x.*
FROM
(
SELECT a.Email, b.Certificate
FROM (SELECT DISTINCT Email FROM StudentCerts) a
CROSS JOIN
(SELECT DISTINCT Certificate FROM CertReqs) b
) x LEFT JOIN studentCerts y
ON x.Email = y.Email AND
x.Certificate = y.Certificate
WHERE y.Email IS NULL AND
x.Email = 'This@that.com'
ORDER BY x.EMAIL
SELECT Certificate FROM `CertReqs`
WHERE Certificate NOT in(
SELECT Certificate
FROM `StudentCerts`
WHERE Email = 'This@that.com'
)
SELECT DISTINCT A.* fROM
(
SELECT DISTINCT EMAIL, CERTIFICATE fROM #StudentCerts A
CROSS JOIN #CertReqs B) A
LEFT JOIN #StudentCerts B ON A.EmaiL = B.EMAIL AND B.CERTIFICATES = A.Certificate
WHERE B.EMAIL IS NULL
ORDER BY A.EMAIL
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