[英]Query a recordset
我正在尝试找出如何将$ sql_pay_det查询移到$ sql_pay循环之外(因此实际上是在$ rs_pay_det上进行查询,而不是为循环的每次迭代创建一个新的$ rs_pay_det)
目前,我的代码如下所示:
//Get payroll transactions
$sql_pay = 'SELECT Field1, DescriptionandURLlink, Field5, Amount, Field4, PeriodName FROM tblgltransactionspayroll WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND PeriodNo = "'.$month.'"';
$rs_pay = mysql_query($sql_pay);
$row_pay = mysql_fetch_assoc($rs_pay);
while($row_pay = mysql_fetch_array($rs_pay))
{
$employee_name = $row_pay['Field1'];
$assign_no = $row_pay['DescriptionandURLlink'];
$pay_period = $row_pay['Field5'];
$mth_name = $row_pay['PeriodName'];
$amount = $row_pay['Amount'];
$total_amount = $total_amount + $amount;
$amount = my_number_format($amount, 2, ".", ",");
$sql_pay_det = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM tblpayrolldetail WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND AccountingPeriod = "'.$mth_name.'" AND EmployeeRef = "'.$assign_no.'"';
$rs_pay_det = mysql_query($sql_pay_det);
$row_pay_det = mysql_fetch_assoc($rs_pay_det);
while($row_pay_det = mysql_fetch_array($rs_pay_det))
{
$element_det = $row_pay_det['ElementDesc'];
$amount_det = $row_pay_det['Amount'];
$wte_worked = $row_pay_det['WTEWorked'];
$wte_paid = $row_pay_det['WTEPaid'];
$wte_cont = $row_pay_det['WTEContract'];
$payscale = $row_pay_det['Payscale'];
//Get band/point and annual salary where element is basic pay
if ($element_det =="3959#Basic Pay"){
$sql_payscale = 'SELECT txtPayscaleName, Salary FROM tblpayscalemapping WHERE txtPayscale = "'.$payscale.'"';
$rs_payscale = mysql_query($sql_payscale);
$row_payscale = mysql_fetch_assoc($rs_payscale);
$grade = $row_payscale['txtPayscaleName'];
$salary = "£" . my_number_format($row_payscale['Salary'], 0, ".", ",");
}
}
}
我尝试这样做:
//Get payroll transactions
$sql_pay = 'SELECT Field1, DescriptionandURLlink, Field5, Amount, Field4, PeriodName FROM tblgltransactionspayroll WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND PeriodNo = "'.$month.'"';
$rs_pay = mysql_query($sql_pay);
$row_pay = mysql_fetch_assoc($rs_pay);
//Get payroll detail recordset
$sql_pay_det = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale, EmployeeRef FROM tblpayrolldetail WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND AccountingPeriod = "'.$mth_name.'"';
$rs_pay_det = mysql_query($sql_pay_det);
while($row_pay = mysql_fetch_array($rs_pay))
{
$employee_name = $row_pay['Field1'];
$assign_no = $row_pay['DescriptionandURLlink'];
$pay_period = $row_pay['Field5'];
$mth_name = $row_pay['PeriodName'];
$amount = $row_pay['Amount'];
$total_amount = $total_amount + $amount;
$amount = my_number_format($amount, 2, ".", ",");
//Query $rs_pay_det
$sql_pay_det2 = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM ('.$sql_pay_det.') tpd WHERE EmployeeRef = "'.$assign_no.'"';
$rs_pay_det2 = mysql_query($sql_pay_det2);
$row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);
while($row_pay_det2 = mysql_fetch_array($rs_pay_det2))
{
$element_det = $row_pay_det2['ElementDesc'];
$amount_det = $row_pay_det2['Amount'];
$wte_worked = $row_pay_det2['WTEWorked'];
$wte_paid = $row_pay_det2['WTEPaid'];
$wte_cont = $row_pay_det2['WTEContract'];
$payscale = $row_pay_det2['Payscale'];
//Get band/point and annual salary where element is basic pay
if ($element_det =="3959#Basic Pay"){
$sql_payscale = 'SELECT txtPayscaleName, Salary FROM tblpayscalemapping WHERE txtPayscale = "'.$payscale.'"';
$rs_payscale = mysql_query($sql_payscale);
$row_payscale = mysql_fetch_assoc($rs_payscale);
$grade = $row_payscale['txtPayscaleName'];
$salary = "£" . my_number_format($row_payscale['Salary'], 0, ".", ",");
}
}
}
但是我在$ row_pay_det2上收到一个错误,说“ mysql_fetch_assoc():提供的参数不是有效的MySQL结果资源”
您的subquery
语法( ... FROM "'.$rs_pay_det.'" ...
)错误。
根据手册-dev.mysql.com/doc/refman/5.0/en/from-clause-subqueries.html
子查询在SELECT语句的FROM子句中是合法的。 实际语法为:
SELECT ... FROM(子查询)[AS]名称...
尝试更改为-
$sql_pay_det2 = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM ('.$sql_pay_det.') tpd WHERE EmployeeRef = "'.$assign_no.'"';
编辑-问题2
由于具有重复的代码(mysql_fetch_assoc()和mysql_fetch_array()),使用mysql_fetch_assoc()
之后, moves the internal data pointer ahead
您只会在数据集中获得第二行。 因此,当您执行mysql_fetch_array()
,将获得除第一行以外的每一行。
//Get payroll transactions
...
$row_pay = mysql_fetch_assoc($rs_pay);
//Get payroll detail recordset
...
while($row_pay = mysql_fetch_array($rs_pay))
{
...
$row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);
while($row_pay_det2 = mysql_fetch_array($rs_pay_det2))
{
...
}
}
}
您需要删除- $row_pay = mysql_fetch_assoc($rs_pay);
& $row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);
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