![](/img/trans.png)
[英]How we can connect the wifi scan results to specific ssid network and want to launch app?
[英]Scanning available wifi, detect specific strongest Wifi SSID to launch an XML activity layout
我需要通过扫描可用的最强大的Wifi来启动活动来定位建筑物中的当前位置。 我只想在那座建筑物中找到3个地方。 因此,如果我当前在这些位置中的任何一个附近,我将单击一个按钮来扫描可用的最强大的Wifi以启动活动。
到目前为止,我已经具有扫描最强大的Wifi的编码。 但是当检测到最强的特定Wifi SSID时,我不知道如何启动活动。 我不需要有关Wifi的信息,只需启动包含我的信息的活动布局即可。
目前,我正在使用以下代码来扫描从此处获得的最强的Wifi信号:
WiFiDemo.java
public class WiFiDemo extends Activity implements OnClickListener {
private static final String TAG = "WiFiDemo";
WifiManager wifi;
BroadcastReceiver receiver;
TextView textStatus;
Button buttonScan;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// Setup UI
textStatus = (TextView) findViewById(R.id.textStatus);
buttonScan = (Button) findViewById(R.id.buttonScan);
buttonScan.setOnClickListener(this);
// Setup WiFi
wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
// Get WiFi status
WifiInfo info = wifi.getConnectionInfo();
textStatus.append("\n\nWiFi Status: " + info.toString());
// List available networks
List<WifiConfiguration> configs = wifi.getConfiguredNetworks();
for (WifiConfiguration config : configs) {
textStatus.append("\n\n" + config.toString());
}
// Register Broadcast Receiver
if (receiver == null)
receiver = new WiFiScanReceiver(this);
registerReceiver(receiver, new IntentFilter(
WifiManager.SCAN_RESULTS_AVAILABLE_ACTION));
Log.d(TAG, "onCreate()");
}
@Override
public void onStop() {
unregisterReceiver(receiver);
}
public void onClick(View view) {
Toast.makeText(this, "On Click Clicked. Toast to that!!!",
Toast.LENGTH_LONG).show();
if (view.getId() == R.id.buttonScan) {
Log.d(TAG, "onClick() wifi.startScan()");
wifi.startScan();
}
} }
WiFiScanReceiver.java
public class WiFiScanReceiver extends BroadcastReceiver {
private static final String TAG = "WiFiScanReceiver";
WiFiDemo wifiDemo;
public WiFiScanReceiver(WiFiDemo wifiDemo) {
super();
this.wifiDemo = wifiDemo;
}
@Override
public void onReceive(Context c, Intent intent) {
List<ScanResult> results = wifiDemo.wifi.getScanResults();
ScanResult bestSignal = null;
for (ScanResult result : results) {
if (bestSignal == null
|| WifiManager.compareSignalLevel(bestSignal.level, result.level) < 0)
bestSignal = result;
}
String message = String.format("%s networks found. %s is the strongest.",
results.size(), bestSignal.SSID);
Toast.makeText(wifiDemo, message, Toast.LENGTH_LONG).show();
Log.d(TAG, "onReceive() message: " + message);
}
}
您只需要从onReceive开始活动。 除非我不理解您的问题,否则您只需要激活您的活动即可。 由于您在接收者的onReceive上具有上下文,因此只需要startActivity()
在onReceive BroadcastReceiver内部启动活动
@Override
public void onReceive(Context context, Intent intent) {
//start activity
Intent i = new Intent();
i.setClassName("com.test", "com.test.MainActivity");
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
不要忘记在清单中为其定义一个适当的过滤器。 http://developer.android.com/reference/android/content/BroadcastReceiver.html
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.