[英]Use JSON variable as public variable?
我正在将Flickr集加载到我的网站中,如下所示:
$(window).load(function() {
var apiKey = 'xxx';
var userId = '8378546@N08';
$.getJSON('http://api.flickr.com/services/rest/?format=json&method=flickr.photosets.getPhotos&photoset_id=' + photoset_id + '&per_page=1000' + '&page=1' + '&api_key=' + apiKey + '&user_id=' + userId + '&jsoncallback=?', function(data) {
$.each(data.photoset.photo, function(i, flickrPhoto){
var basePhotoURL = 'http://farm' + flickrPhoto.farm + '.static.flickr.com/'
+ flickrPhoto.server + '/' + flickrPhoto.id + '_' + flickrPhoto.secret + "_z.jpg";
var fullPhotoURL = 'http://farm' + flickrPhoto.farm + '.static.flickr.com/'
+ flickrPhoto.server + '/' + flickrPhoto.id + '_' + flickrPhoto.secret + "_l.jpg";
/*var FlickrLink = "http://www.flickr.com/photos/" + data.photoset.owner + "/" + flickrPhoto.id + "/";*/
$("<img/>").attr("src", basePhotoURL).appendTo("#photographs").wrap(("<div class='item'></div>"))
});
**$("<a href='#' class='zoom'/>").appendTo(".item");**
**$("<a href='#' class='flickr'/>").appendTo(".item");**
$("#photographs").gridalicious({
gutter: 2,
animate: true,
effect: 'fadeInOnAppear',
width: 320,
complete: onComplete()
});
function onComplete(){
$("#loader").delay(20000).fadeOut("slow");
$(".item").hover(function(){
$(".zoom, .flickr", this).stop(true,true).fadeIn(300);
}, function () {
$(".zoom, .flickr", this).stop(true,true).fadeOut(300);
});
}
});
});
.zoom和.flickr div附加到.item div(包含图片)。 我需要var fullPhotoURL和var FlickrLink,因为我想在代码的突出显示(带有星号)锚点中使用它们。 当我这样做时,我得到一个错误,即找不到 var fullPhotoURL和var FlickrLink 。
我该如何解决?
您必须在$ .each块之外定义变量:
$.getJSON('http://api.flickr.com/services/rest/?format=json&method=flickr.photosets.getPhotos&photoset_id=' + photoset_id + '&per_page=1000' + '&page=1' + '&api_key=' + apiKey + '&user_id=' + userId + '&jsoncallback=?', function(data) {
var fullPhotoURL, FlickrLink;
$.each(data.photoset.photo, function(i, flickrPhoto){
var basePhotoURL = 'http://farm' + flickrPhoto.farm + '.static.flickr.com/'
+ flickrPhoto.server + '/' + flickrPhoto.id + '_' + flickrPhoto.secret + "_z.jpg";
fullPhotoURL = 'http://farm' + flickrPhoto.farm + '.static.flickr.com/'
+ flickrPhoto.server + '/' + flickrPhoto.id + '_' + flickrPhoto.secret + "_l.jpg";
/*FlickrLink = "http://www.flickr.com/photos/" + data.photoset.owner + "/" + flickrPhoto.id + "/";*/
$("<img/>").attr("src", basePhotoURL).appendTo("#photographs").wrap(("<div class='item'></div>"))
});
$("<a href='#' class='zoom'/>").appendTo(".item");
要在Javascript中定义全局变量,您需要跳过var
声明项。
var
“均值” lacal变量
首先给变量赋一个默认值:
fullPhotoURL = null;
FlickrLink = null; //Avoid first upcase char to define variable
然后这些变量将在所有功能中可用
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