繁体   English   中英

PHP(URL)匹配正则表达式问题

[英]PHP (URL) matching regex issue

我正在寻找一个正则表达式来匹配给定的URL,其中包含类似
"/unknownnumber/knownstring1-unknownstring.html"
为了用PHP将其重定向到其他新网址,例如
"/unknownnumber/knownstring2-unknownstring"
使Google索引网址保持活动状态。

我使用了next语句,但是$do_match返回0 ,所以我做错了...
有人可以帮我做正则表达式吗?

$myURL = "/unknownnumber/knownstring1-unknownstring.html";
$do_match = preg_match('~"([0-9]+)/knownstring1-(.*?)$.html"~', $myURL, $matches);

点(。),破折号(-)是具有特殊含义的元字符。

如果'unknownumber'是字符串的数字部分,则regexp模式如下所示:

$do_match = preg_match('/\/(\d+)\/knownstring1\-([^\.]+)\.html/', $input, $matches);

$是行尾标记。 您需要将其放在正则表达式的末尾,也要表示文字. 你需要逃脱它。

preg_match('~"([0-9]+)/knownstring1-(.*?)\.html"$~'....
$myURL = "/unknownnumber/knownstring1-unknownstring.html";
if(preg_match('#"/(\d+)/knownstring1-(.*)\.html"#', $myURL, $matches))
    var_dump($matches);

输出:

php > $exp = '#"/(\d+)/knownstring1-(.*)\.html"#';
php > $str = '"/23421/knownstring1-unknownstring.html"';
php > if(preg_match($exp, $str, $matches)) var_dump($matches); else echo 'nope' .     PHP_EOL;
array(3) {
  [0]=>
  string(40) ""/23421/knownstring1-unknownstring.html""
  [1]=>
  string(5) "23421"
  [2]=>
  string(13) "unknownstring"
}
php > 

试试看:

$myURL = "/123/knownstring1-unknownstring.html";
$do_matches = preg_match('#\/(\d+)\/(.*)\-(.*)\.html#', $myURL, $matches);
print_r($matches);

print_r输出:

Array
(
    [0] => /123/knownstring1-unknownstring.html
    [1] => 123
    [2] => knownstring1
    [3] => unknownstring
)

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM