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[英]Feeding data into database with Php form and using that data into JSON format to be used in D3
[英]Format data for D3
如何格式化我在d3.js中制作的图表的示例数据?
[
[
[
"2",
"2013-01-02 00:00:00+00"
],
[
"3",
"2012-12-28 00:00:00+00"
],
[
"3",
"2012-12-27 00:00:00+00"
],
[
"1",
"2012-12-26 00:00:00+00"
],
[
"1",
"2012-12-24 00:00:00+00"
],
[
"4",
"2012-12-21 00:00:00+00"
],
[
"1",
"2012-12-20 00:00:00+00"
]
],
[
[
"1",
"2012-12-27 00:00:00+00"
],
[
"2",
"2012-12-21 00:00:00+00"
],
[
"2",
"2012-12-18 00:00:00+00"
],
[
"1",
"2012-12-17 00:00:00+00"
],
[
"1",
"2012-11-27 00:00:00+00"
],
[
"1",
"2012-11-03 00:00:00+00"
],
[
"1",
"2012-10-27 00:00:00+00"
]
]
]
目前,我的javascript控制台给了我Uncaught TypeError: Cannot use 'in' operator to search for '_dateElement' in NaN
当d3尝试解析这些数据时, Uncaught TypeError: Cannot use 'in' operator to search for '_dateElement' in NaN
:1033
似乎d3不想处理引号中的数字,没有引号使得json无效,我的ajax调用将不会返回,这意味着我将无法在d3函数中解析数组。
我相信d3可以解析和格式化json,但我陷入了僵局。 如何格式化此数据,日期对象将按升序排列为我的X轴,Y轴将是整数值的最大值
您需要将输入数组解析为输出数组,其中包含所需格式的数据。 正如C.Reed在评论中所说,使用parseInt将字符串转换为数字并使用d3.time.format将字符串转换为日期。 https://github.com/mbostock/d3/wiki/Time-Formatting
var date_in = "2013-01-02 00:00:00+00";
var format = d3.time.format("%Y-%m-%d 00:00:00+00");
var date_out = format.parse(date_in);
(假设时间总是0)
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