选择sum where where子句SQL

Question

我有以下代码，它可以工作，但我试图为每个Banksphere.servicio_id列分隔SUM，这个代码SUM只有一个servicio_id ...我有点迷失，有人可以帮帮我吗？

正如你所看到的，每个WHERE子句都是完全相同的但是Banksphere.peticion_id是唯一一个改变的...所以也许有一些更好的方法来过滤一下常用的子句并且只留下peticion_id用于OK和KO？

SELECT
(SELECT
    SUM(valor)
FROM
    Banksphere
WHERE
    Banksphere.fecha = '2013-01-14'
AND
    Banksphere.servicio_id = '6'
AND
    Banksphere.entidad_id = '2'
AND
    Banksphere.peticion_id = '0') AS OK,
(SELECT
    SUM(valor)
FROM
    Banksphere
WHERE
    Banksphere.fecha = '2013-01-14'
AND
    Banksphere.servicio_id = '6'
AND
    Banksphere.entidad_id = '2'
AND
    Banksphere.peticion_id = '1') AS KO

使用工作代码编辑

SELECT  Servicios.nombre as servicio,
        SUM(case when peticion_id = '0' then valor end) as OK,
        SUM(case when peticion_id = '1' then valor end) as KO
FROM    Banksphere
INNER JOIN
    Servicios
ON
    Banksphere.servicio_id = Servicios.id
WHERE   Banksphere.fecha = '2013-01-14'
        AND Banksphere.entidad_id = '2'
        AND Banksphere.peticion_id in ('0', '1')
group by Servicios.nombre

Answer 1

我想你想要这样的东西：

SELECT  banksphere.servicio_id, SUM(valor),
        SUM(case when peticion_id = '0' then valor end) as OK,
        SUM(case when peticion_id = '1' then valor end) as KO
FROM    Banksphere
WHERE   Banksphere.fecha = '2013-01-14'
        AND Banksphere.entidad_id = '2'
        AND Banksphere.peticion_id in ('0', '1', ...)
group by banksphere.servicio_id

这有一个group by所以你可以得到多个“servicio_ids”，它为OK和KO添加了单独的列。 如果只想要servicio_id = 6，那么将其添加回where子句。 并且，您可能也希望group by其他变量，但您只在问题中提及服务。

Answer 2

SELECT  servicio_id,
        entidad_id,
        SUM(CASE WHEN peticion_id = 0 THEN valor ELSE 0 END) OK,
        SUM(CASE WHEN peticion_id = 1 THEN valor ELSE 0 END) KO
FROM    BankSpehere
WHERE   fecha = '2013-01-14' AND 
        entidad_id = '2' AND 
        peticion_id in ('0', '1')
GROUP BY servicio_id, entidad_id

Answer 3

SELECT  SUM(valor)
FROM    Banksphere
WHERE   Banksphere.fecha = '2013-01-14'
        AND Banksphere.servicio_id = '6'
        AND Banksphere.entidad_id = '2'
        AND Banksphere.peticion_id in ('0', '1', ...)