[英]select rows where column values differ by more than two years
所以我的桌子有这样的记录
ID PRODUCT MAKE_DATE ORDER_DATE
1 aaaa 2010-11-04 2051-12-11 16:13:43
2 bbb 2011-10-05 2010-11-11 00:00:00
3 cccc 2010-05-20 0000-00-00 00:00:00
我的问题:如何在make_date
与order_date
不同的情况下显示那些结果2年?
IM卡在此:
Select ID, Product, make_date, order_datetime
FROM `tbl_order`
WHERE make_date ??? order_datetime
结果应该是:
1 aaaa 2010-11-04 2051-12-11 16:13:43
3 cccc 2010-05-20 0000-00-00 00:00:00
Select ID, Product, make_date, order_datetime
FROM tbl_order
WHERE make_date < order_datetime - INTERVAL 2 YEAR
OR make_date > order_datetime + INTERVAL 2 YEAR ;
对于MySQL使用TIMESTAMPADD
函数:
SELECT ID, Product, make_date, order_datetime
FROM `tbl_order`
WHERE make_date > TIMESTAMPADD(YEAR, 2, order_datetime)
OR make_date < TIMESTAMPADD(YEAR, -2, order_datetime)
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