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[英]How to Sum a series of rows in MYSQL from one Table, matching the info from another to get the result
[英]Show result from one table depending on info from another MySQL table
我一直试图解决这个问题很长一段时间,我放弃了。 我从一张桌子上获取信息,没问题。 但我需要根据另一个表中的信息排除一些结果。
querylist
id | artist | title
1 | Kelly Clarkson | Catch My Breath
2 | Nicki Minaj | Va Va Voom
3 | Jingle | Jingle100
songlist
id | artist | title | songtype
1 | Kelly Clarkson | Catch My Breath | S
2 | Nicki Minaj | Va Va Voom | S
3 | Jingle | Jingle100 | I
当我从querylist表中得到我的结果时,我想从songlist表中排除所有没有songtype S的歌曲。
我有这个,我怎么只用歌曲S来获得歌曲?
$result = mysql_query("SELECT * FROM queuelist q LEFT JOIN requestlist r ON q.requestid = r.id LEFT JOIN songlist s ON q.songid = s.id ORDER BY q.sortID ASC LIMIT 5 ",$dbcon);
echo "<table>\n";
if ($myrow = mysql_fetch_array($result)){
do{
$artist = $myrow["artist"];
$title = $myrow["title"];
echo "<tr><td>$artist - $title</td>";
echo "</tr>\n";
}while($myrow = mysql_fetch_array($result));
}
echo "</table>";
只是要明确:添加:WHERE s.songtype ='S'
SELECT * FROM queuelist q
LEFT JOIN requestlist r ON q.requestid = r.id
LEFT JOIN songlist s ON q.songid = s.id
WHERE s.songtype='S'
ORDER BY q.sortID ASC LIMIT 5
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