在php中从数据库中获取结果，并将其输出为循环以在javascript中显示

Question

我有这段代码即时通讯正在尝试输出此：

{
    title:"<?php echo $sender_fullname; ?>",
    mp3:"link",
},

在php中使用它在javascript中显示它

//database include
require_once "db.php";

//get email from session 
$email = $_SESSION['username'];

//fetch user fullname and  id based on session
$name_query = mysql_query("SELECT fullname,id FROM users WHERE email = '$email'");
$name = mysql_fetch_object($name_query);

//fecth sender id, receiver id, audioclip, fullname and email
$query = "SELECT m.sender,m.receiver, m.audioclip, u.fullname, u.email 
                     FROM `users` AS u 
                     JOIN `messages` AS m ON m.receiver = u.id 
                     WHERE u.email = '".$email."'";

$result = mysql_query($query); 

这是循环我应该怎么做才能输出相同的

while(
        $row = mysql_fetch_assoc($result)) { 
        $sender = $row['sender'];
        $sender_name_query = mysql_query("SELECT fullname FROM users WHERE id = '$sender'");
        $sender_name = mysql_fetch_object($sender_name_query);
        $sender_fullname = $sender_name->fullname;
        echo '{<br/>title:".'$sender_fullname'.",<br/>mp3:"link",<br/>},';      
    }   

Answer 1

你可以做一些像：

while(
        $row = mysql_fetch_assoc($result)) { 
        $sender = $row['sender'];
        $sender_name_query = mysql_query("SELECT fullname FROM users WHERE id = '$sender'");
        $sender_name = mysql_fetch_object($sender_name_query);
        $sender_fullname = $sender_name->fullname;
        echo '{<br/>title:".'$sender_fullname'.",<br/>mp3:"link",<br/>},';
        print "<script>alert(\"$sender_fillname\")</script>";
    }

然后，如果要将php变量的值放入javascript变量中，可以将脚本标记中的代码像javascript代码一样运行：

<?
    $mivar = "hola mundo";
    print "<script>";
    print "var mivar = \"$mivar\"";
    print "</script>";
?>

Answer 2

使php进入javascript的最好方法是通过php的json_encode使用JSON。

$rows = array();
while($row = mysql_fetch_assoc($result)) { 
    $sender = $row['sender'];
    $sender_name_query = mysql_query("SELECT fullname FROM users WHERE id = '$sender'");
    $sender_name = mysql_fetch_object($sender_name_query);
    $sender_fullname = $sender_name->fullname;
    $row['sender'] = $sender_fullname;
    $rows[] = $row;
}   

echo "<script type='text/javascript'>";
echo "var rows = " . json_encode($rows) . ";";
echo "</script>";

Answer 3

该错误是由最后一行引起的：

echo '{<br/>title:".'$sender_fullname'.",<br/>mp3:"link",<br/>},';

应该是这样的：

echo '{<br/>title:"' . $sender_fullname . '",<br/>mp3:"link",<br/>},';

---

注1

您可以这样写：

$sender_fullname = $sender_name->fullname;
echo '{<br/>title:"' . $sender_fullname . '",<br/>mp3:"link",<br/>},';

容易地作为：

echo '{<br/>title:"' . $sender_name->fullname. '",<br/>mp3:"link",<br/>},';

---

笔记2

请不要在新代码中使用mysql_*函数 。 它们不再维护，已正式弃用 。 看到红色框了吗？ 而是了解准备好的语句 ，并使用PDO或MySQLi- 本文将帮助您确定哪一个。 如果您选择PDO， 这是一个很好的教程 。

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