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无法使用xstream将xml字符串反序列化为扩展的genericType的对象

[英]Cannot deserialize xml string to the extended genericType's Object using xstream

首先,我想显示我的Core代码以反序列化xml String

    public XMLClient<T> xmlToClient(String xmlString,T t) throws Exception{
    //according to the generic class's name,insert the name after input tag
    //to make the xstream to know which class is going to deserialize to
        String insertClassName = t.getGenericTypeRecord();
        xmlString.replaceAll("<INPUT>", "<INPUT input."+insertClassName+">");
        XMLClient<T> xmlClient = new XMLClient<T>();
        XStream xs = new XStream(new DomDriver());
        xs.processAnnotations(XMLClient.class);
        xmlClient = (XMLClient<T>)xs.fromXML(xmlString);
        logger.info(xmlString);
        return xmlClient;
    }

T是从超级基类扩展的类。 就像

T扩展baseInputXml

但是当应用程序运行在

xmlClient = (XMLClient<T>)xs.fromXML(xmlString);

会出现错误消息,告诉我XMLClient中没有匹配的属性。尽管该属性在超级T类中不存在,但在子T类中存在

我希望您能理解我的想法,我对这些genericType和xstream convert感到非常困惑,谢谢

xs.processAnnotations(XMLClient.class);

该行应编辑为

xs.processAnnotations(XMLClient.class);
xs.processAnnotations(XMLClientsSuperClass.class);

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