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[英]OOP - A member function of one class inside a member function of another class
[英]How to access member function of one class inside another class?
我无法在另一个类中访问一个类的成员函数,尽管我可以在main()中访问它。 我一直试图改变现状,但我无法理解我做错了什么。 任何帮助,将不胜感激。
以下是生成错误的行:
cout << "\n\nRetrieve key from inside Envelope class: " << e.getData() << "\n\n";
以下是代码:
class Record{
private:
string key;
public:
Record(){ key = ""; }
Record(string input){ key = input; }
string getData(){ return key; }
Record operator= (string input) { key = input; }
};
template<class recClass>
class Envelope{
private:
recClass * data;
int size;
public:
Envelope(int inputSize){
data = new recClass[inputSize];
size = 0;
}
~Envelope(){ delete[] data; }
void insert(const recClass& e){
data[size] = e;
cout << "\n\nRetrieve key from inside Envelope class: " << e.getData() << "\n\n";
++size;
}
string getRecordData(int index){ return data[index].getData(); }
};
int main(){
Record newRecord("test");
cout << "\n\nRetrieve key directly from Record class: " << newRecord.getData() << "\n\n";
Envelope<Record> * newEnvelope = new Envelope<Record>(5);
newEnvelope->insert(newRecord);
cout << "\n\nRetrieve key through Envelope class: " << newEnvelope->getRecordData(0) << "\n\n";
delete newEnvelope;
cout << "\n\n";
return 0;
}
您将e
作为常量引用传递void insert(const recClass& e){
然后你调用一个未声明为常量的方法( getData()
)。
您可以通过重写getData()
来修复它:
string getData() const{ return key; }
您必须将getData()
声明为const
以便可以从const
上下文中调用它。 你的insert
函数采用const recClass& e
所以你想在Record
执行此操作:
string getData() const { return key; }
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