[英]from input file to array using malloc and realloc
我正在嘗試從文件中讀取輸入,並使用malloc和realloc將每個字符串放入數組中。 因此,如果輸入文件是:
alex
john
jane
smith
數組的內容包含{“ alex \\ n”,“ john \\ n”,“ jane \\ n”,“ smith \\ n”}。 到目前為止,我已經做了類似的事情:
int n=0;
int size=1;
File *fp = fopen(args[0],"r");
int c;
char* inputFile;
inputFile = (char*) malloc(size);
if(fp==0){
fprintf(stderr, "Cannot open file!\n");
return -1;}
else{
do{
c = fgetc(fp);
inputFile = (char*) realloc(inputFile, size+1);
inputFile[n]=c;
n++;
size++;
}while(c!=EOF);
我相信該算法將以這樣的數組結尾:{'a','l','e','x','\\ n','j','o','h','n',' \\ n','j','a','n','e','\\ n','s','m','i','t','h','\\ n'}
如何使inputFile成為2維數組? 我應該如何處理realloc?
您可能想先分配一個指針數組,其初始大小為10:
int size = 10;
char **inputFile= malloc(sizeof*inputFile*size);
然后,對於每個閱讀的單詞,您為其分配更多的內存,並將其插入數組:
char line[100];
fscanf(file, "%s", line);
inputFile[index++] = strdup(line);
現在檢查是否需要更多單詞,然后重新分配數組:
if (index==size) {
size += 10;
inputFile = realloc(inputFile, sizeof*inputFile*size);
}
因此,您最終會得到如下結果:
[0]->"alex"
[1]->"john"
[2]->"jane"
[3]->"smith"
完成后,您需要遍歷數組並釋放每個字符串,然后釋放數組,這部分留作練習:)
您可以嘗試以下操作,也可以研究如何完成。 它在我的linux機器上工作正常。 如果您有任何疑問,請告訴我。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
const int INITIAL_MAX_LINES = 2;
const int MAX_LINES_INC = 2;
const int INITIAL_MAX_LINE_LENGTH = 2;
const int MAX_LINE_LENGTH_INC = 2;
int main (int argc, char *argv[])
{
int nlines = 0, i;
FILE *fp = fopen(argv[1], "r");
char **inputFile, *buffer;
int max_lines, c, buflen, bufpos, end_of_line;
if (argc < 2) {
printf("No enough arguments.\n");
return -1;
}
max_lines = INITIAL_MAX_LINES;
inputFile = (char **) malloc(max_lines * sizeof(char*));
if (fp==0) {
fprintf(stderr, "Cannot open file!\n");
return -1;
}
else{
/* Start with a buffer. */
bufpos = 0;
buflen = INITIAL_MAX_LINE_LENGTH;
buffer = (char *) malloc(buflen * sizeof(char *));
c = 0;
while (c != EOF) {
end_of_line = 0;
c = fgetc(fp);
if (c == EOF || c == '\n' || c == '\r') {
end_of_line = 1;
/* Discard this character. */
}
else {
/* Put this character in the buffer. */
/* But check if we have enough memory first! */
/* Leave room for the null character at the end. */
if (bufpos >= buflen - 1) {
buflen += MAX_LINE_LENGTH_INC;
buffer = (char *) realloc(buffer, buflen * sizeof(char));
}
buffer[bufpos] = c;
bufpos++;
}
if (end_of_line) {
/* Remember this line and get a new buffer. */
/* Check if we need more memory. */
if (nlines >= max_lines) {
max_lines += MAX_LINES_INC;
inputFile = (char **) realloc(inputFile, max_lines * sizeof(char*));
}
/* Null terminate the buffer.*/
buffer[bufpos++] = 0;
inputFile[nlines] = buffer;
nlines++;
bufpos = 0;
buflen = INITIAL_MAX_LINE_LENGTH;
buffer = (char *) malloc(buflen * sizeof(char *));
}
}
}
printf("%d lines\n", nlines);
for (i=0; i<nlines; i++) {
printf("%s\n", inputFile[i]);
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.