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[英]using hibernate Criteria.uniqueResult() when there are several results
[英]Criteria.uniqueResult is returning null, but no error is thrown
我正在學習休眠,並且正在嘗試查詢表以查找具有特定ID的人。 當我調用criteria.unique結果時,不會引發任何錯誤,但是它返回一個空值,有人可以幫助我弄清楚發生了什么嗎?
@Entity
@Table(name="employees")
public class Employee {
private long emp_no;
private Date birth_date;
private String first_name;
private String last_name;
private char gender;
private Date hire_date;
private Set<DepartmentEmp> department_emp = new HashSet<DepartmentEmp>();
private Set<DepartmentManager> department_manager = new HashSet<DepartmentManager>();
private Set<Projects> projects;
private ContactInfo contactInfo;
public Employee(){};
public Employee(long empt_no, Date birth_date, String first_name, String last_name,
char gender, Date hire_date){
this.emp_no = emp_no;
this.birth_date = birth_date;
this.first_name = first_name;
this.last_name = last_name;
this.gender = gender;
this.hire_date = hire_date;
}
@Id
@Column(name="emp_no")
public long getEmp_no() { return emp_no; }
public void setEmp_no(long emp_no) {this.emp_no=emp_no;}
@Column(name="birth_date")
public Date getBirth_date() { return birth_date; }
public void setBirth_date(Date birth_date) {this.birth_date = birth_date;}
@Column(name="first_name")
public String getFirst_name() { return first_name; }
public void setFirst_name(String name) { this.first_name = name; }
@Column(name="last_name")
public String getLast_name() { return last_name; }
public void setLast_name(String name) { this.last_name = name; }
@Column(name="gender")
public char getGender() { return gender; }
public void setGender(char gender) {this.gender = gender;}
@Column(name="hire_date")
public Date getHire_date() { return hire_date; }
public void setHire_date(Date hire_date) {this.hire_date = hire_date;}
@OneToOne(cascade=CascadeType.ALL, fetch=FetchType.LAZY)
@JoinColumn(name="emp_no")
public ContactInfo getContactInfo() { return contactInfo; }
public void setContactInfo(ContactInfo info) { this.contactInfo = info; }
@OneToMany(mappedBy="employee", targetEntity=DepartmentEmp.class,
cascade=CascadeType.ALL)
@Fetch(value = FetchMode.SELECT)
public Set<DepartmentEmp> getDepartment_emp() { return department_emp; }
public void setDepartment_emp(Set<DepartmentEmp> department_emp) { this.department_emp = department_emp; }
@OneToMany(mappedBy="employee", targetEntity=DepartmentManager.class,
cascade=CascadeType.ALL)
@Fetch(value = FetchMode.SELECT)
public Set<DepartmentManager> getDepartment_manager() { return department_manager; }
public void setDepartment_manager(Set<DepartmentManager> department_manager) { this.department_manager = department_manager; }
@ManyToMany
@JoinTable(name="employee_projects",
joinColumns={@JoinColumn(name="employee_emp_no")},
inverseJoinColumns={@JoinColumn(name="projects_proj_num")})
@Fetch(value = FetchMode.SELECT)
public Set<Projects> getProjects() { return projects; }
public void setProjects(Set<Projects> projects) { this.projects = projects; }
public void print() {
System.out.printf("%d: %s %s %s %c %s\n", emp_no, birth_date.toString(), first_name, last_name, gender, hire_date.toString());
}
public static void list()
{
Session session = HibernateContext.getSession();
Criteria criteria = session.createCriteria(Employee.class);
criteria.addOrder(Order.asc("emp_no"));
List <Employee> employees = criteria.list();
System.out.println("All Employees:");
for (Employee employee : employees) {
employee.print();
}
session.close();
}
//TODO finish 4 methods
public static Employee find(long emp_no){
Employee prototype = new Employee();
prototype.setEmp_no(emp_no);
Example ex = Example.create(prototype);
Session sess = HibernateContext.getSession();
Criteria criteria = sess.createCriteria(Employee.class);
criteria.add(ex);
Employee e = (Employee) criteria.uniqueResult();
return e;
}
public static Employee find(String first, String last){
Employee prototype = new Employee();
prototype.setFirst_name(first);
prototype.setLast_name(last);
Example ex = Example.create(prototype);
Session sess = HibernateContext.getSession();
Criteria criteria = sess.createCriteria(Employee.class);
criteria.add(ex);
Employee e = (Employee) criteria.uniqueResult();
sess.close();
return e;
}
public static void main(String [] args){
Class klasses [] = {Employee.class, DepartmentEmp.class, DepartmentManager.class, ContactInfo.class,
Salaries.class, Titles.class, Department.class, Projects.class};
HibernateContext.addClasses(klasses);
Employee.find((long)10001).print();
}
}
HibernateContext:
public class HibernateContext {
public static AnnotationConfiguration config = null;
public static SessionFactory factory = null;
/**
* sets configuration if null
*/
private static void setConfiguration(){
if(config == null){
config = new AnnotationConfiguration();
config.configure();
}
}
/**
* sets factory if null
*/
private static void setFactory(){
if(factory == null){
setConfiguration();
factory = config.buildSessionFactory();
}
}
/**
* Opens session from the factory
*/
public static Session getSession(){
setFactory();
return factory.openSession();
}
/**
* Creates a schema from the configuration
*/
public static void createSchema(){
setConfiguration();
(new SchemaExport(config)).create(true, true);
}
/**
* Adds a new class object to the database
*/
public static void addClass(Class c){
setConfiguration();
config.addAnnotatedClass(c);
}
/**
* Adds a list of class objects to the database
*/
public static void addClasses(Class classes[]){
for(Class c : classes){
addClass(c);
}
}
}
我忽略了其他類,因為它們沒有參與此查詢,但是當我在Employee中運行main函數時,堆棧跟蹤僅在find.print()上顯示空指針異常。 線。 我知道該數據庫已填充,並且運行Employee.list()只能找到它,所以我正在努力弄清楚到底是什么錯誤。 謝謝您的幫助!
在沒有stacktrace的情況下,很難找到問題所在,這是我在猜測的內容:
如果我們看到您的打印方法;
public void print() {
System.out.printf("%d: %s %s %s %c %s\n", emp_no, birth_date.toString(),
first_name, last_name, gender,
hire_date.toString());
}
即使Employee對象在print
正確返回了..如果您未將hire_date
給employee object
並嘗試調用hire_date.toString(),您仍將獲得hire_date
的值,但它將給出null pointer exception
。
確保返回的Employee對象是否具有hire_date
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