DateTime 按日期和小時分組

Question

我有一個名為activity_dt的日期時間，數據如下所示：

2/5/2013 9:24:00 AM
2/7/2013 7:17:00 AM

我如何按日期和時間分組？

Answer 1

SQL 服務器：

SELECT [activity_dt], count(*)
FROM table1
GROUP BY DATEPART(day, [activity_dt]), DATEPART(hour, [activity_dt]);

甲骨文：

SELECT [activity_dt], count(*)
FROM table1
GROUP BY TO_CHAR(activity_dt, 'DD'), TO_CHAR(activity_dt, 'hh');

MySQL：

SELECT [activity_dt], count(*)
FROM table1
GROUP BY hour( activity_dt ) , day( activity_dt )

Answer 2

使用 MySQL 我通常這樣做：

SELECT count( id ), ...
FROM quote_data
GROUP BY date_format( your_date_column, '%Y%m%d%H' )
order by your_date_column desc;

或者以同樣的想法，如果您需要輸出日期/小時：

SELECT count( id ) , date_format( your_date_column, '%Y-%m-%d %H' ) as my_date
FROM  your_table 
GROUP BY my_date
order by your_date_column desc;

如果您在日期列上指定索引，MySQL 應該能夠使用它來稍微加快速度。

Answer 3

SELECT [activity_dt], COUNT(*) as [Count]
  FROM 
 (SELECT dateadd(hh, datediff(hh, '20010101', [activity_dt]), '20010101') as [activity_dt]
    FROM table) abc
 GROUP BY [activity_dt]

Answer 4

就我而言……使用 MySQL：

SELECT ... GROUP BY TIMESTAMPADD(HOUR, HOUR(columName), DATE(columName))