如何檢查日期是否已過期PHP中的數值

Question

大家好，我可以說有一位成員花了20天的時間。 因此，如果有成員20天后，讓我們說不登錄它將更改那里的狀態。 但是僅基於狀態更改日期，該狀態更改日期寫在MySQL數據庫中為year-month-day 。 因此，如果在他的狀態更改日期之前完成了20天，那么他的狀態將會更改。

如果您能幫助我做到這一點，我將不勝感激！

大衛

更新：

碼：

$newStatus = "Non-Active - Driver Chose Non-Compliance";

    $sql = "SELECT username,ATF FROM members WHERE username = 'test'";
    $getcsvuser = $DBH->prepare($sql);
    $getcsvuser->execute();
    while($row = $getcsvuser->fetch(PDO::FETCH_ASSOC)){

        $memusername = $row['username'];
        $memATF = $row['ATF'];
        if ($memATF != 0 || $memATF != "0")
        {
        $tsql = "SELECT username,status,memberview ,statuschangedate FROM csvdata WHERE memberview =:user";
        $tgetcsvuser = $DBH->prepare($tsql);
        $tgetcsvuser->execute(array(':user' => $memusername));
        while($trow = $tgetcsvuser->fetch(PDO::FETCH_ASSOC)){

            $csvstatus = $trow['status'];
            $csvusername = $trow['username'];
            $csvdate = $trow['statuschangedate'];

            if($csvstatus == "Open" || $csvstatus == "Enrolled - Policyholder Follow-Up Required" || $csvstatus == "Enrolled - Employee Follow-Up Required" || $csvstatus == "Non-Active - Insurance Cancelled" || $csvstatus == "Non-Active, Unable to Monitor - Incidental Business use Exclusion" || $csvstatus == "Non-Active - Employee Not Covered Under Listed Policy" || $csvstatus == "Non-Active - PolicyHolder Cancelled Additional Interest")
            {

                $newsql = "UPDATE csvdata SET status = :newstatus WHERE statuschangedate < NOW() - INTERVAL :atf DAY AND username =:mem";
                $newgetcsvuser = $DBH->prepare($newsql);
                $newgetcsvuser->execute(array(':newstatus' => $newStatus, ':atf' => $memATF, ':mem' => $csvusername));
                while($rrow = $newgetcsvuser->fetch(PDO::FETCH_ASSOC)){
                    echo "working";
                }
            }

        }
        }

    }

Answer 1

它可以是兩件事的組合：

mysql更新要更改的用戶：

update
  members
set
  status = 'foo'
where
  status_change_date < NOW() - INTERVAL 20 DAY

第二部分是cron作業，每天運行該查詢。

Answer 2

那個怎么樣：

UPDATE tablename
SET inactive = 1
WHERE date_field < DATE_SUB(NOW(), INTERVAL 20 DAY)

您可以每晚一次作為cronjob運行此查詢。

因此，除了執行此SQL查詢外，無需使用PHP邏輯即可完成此操作。

Answer 3

我沒有測試過，但是應該很接近。

//$dbVal = $row["databaseColumn"];
$dbVal = "2013-01-24";  //For example
$now = Date();

$diff = abs($now - strtotime($dbVal));

$daysSince = floor(($diff/(60*60*24));
if ($daysSince >20){
    //Set status in DB;
}

合並@popnoodles解決方案：

//$dbVal = $row["databaseColumn"];
$dbVal = "2013-01-24";  //For example
$expireTime = 20;

$diff = strtotime($dbVal) - strtotime("today - $expireTime days");
if ($diff < 0 ){
    //Set status in DB;
}