使用分組依據每2分鍾對數據進行分組

Question

我有一個數據庫，該數據庫查找每分鍾的位數，並使用group by語句對它們進行group by 。 我想知道，如何使用相同的group by語句對每2分鍾的totalBits進行分組和求和？

這是我每分鍾要分組的一組查詢

SELECT SUM(totalBits ) AS totalBits,
EXTRACT( YEAR FROM timeStampID ) AS YEAR,
EXTRACT( MONTH FROM timeStampID ) AS MONTH ,
EXTRACT( DAY FROM timeStampID ) AS DAY ,
EXTRACT( HOUR FROM timeStampID ) AS HOUR ,
EXTRACT( MINUTE FROM timeStampID ) AS MINUTE ,
EXTRACT( SECOND FROM timeStampID ) AS SECOND FROM  `ipByteReceive1`
WHERE  `timeStampID` >  '2013-01-21 08:58:55'
GROUP BY YEAR, MONTH , DAY , HOUR, MINUTE

這就是我得到的：

totalBits | YEAR | MONTH | DAY | HOUR | MINUTE
----------+------+-------+-----+------+--------
459       | 2013 | 1     | 21  | 8    | 58
2         | 2013 | 1     | 21  | 8    | 59
17        | 2013 | 1     | 21  | 9    | 00

這就是我想要得到的：

totalBits | YEAR | MONTH | DAY | HOUR | MINUTE
----------+------+-------+-----+------+--------
461       | 2013 | 1     | 21  | 8    | 58
17        | 2013 | 1     | 21  | 9    | 00

提前致謝！

Answer 1

只需更改您提取分鍾的方式，使其也按2進行分組，然后放第二秒（因為它將不再意味着任何內容）。

SELECT SUM(totalBits ) AS totalBits,
EXTRACT( YEAR FROM timeStampID ) AS YEAR, 
EXTRACT( MONTH FROM timeStampID ) AS MONTH ,
EXTRACT( DAY FROM timeStampID ) AS DAY , 
EXTRACT( HOUR FROM timeStampID ) AS HOUR , 
EXTRACT( MINUTE FROM timeStampID ) - MOD(EXTRACT( MINUTE FROM timeStampID ), 2) AS MINUTE , 
WHERE  `timeStampID` >  '2013-01-21 08:58:55'
GROUP BY YEAR, MONTH , DAY , HOUR, MINUTE 

Answer 2

您應該按MINUTE - MOD(MINUTE,2)分組（因此，請選擇該行而不是當前選擇的列）。