[英]SQL Table not updating in PHP
我正在嘗試在PHP中創建更新功能,但記錄似乎並未根據更新進行更改。 我創建了一個JSON對象來保存傳遞到該文件的值,並且根據Firebug Lite控制台,我運行這些值的輸出很好,因此sql端可能出現問題。 誰能發現問題? 非常感謝您的幫助!
<?php
$var1 = $_REQUEST['action']; // We dont need action for this tutorial, but in a complex code you need a way to determine ajax action nature
$jsonObject = json_decode($_REQUEST['outputJSON']); // Decode JSON object into readable PHP object
$name = $jsonObject->{'name'}; // Get name from object
$desc = $jsonObject->{'desc'}; // Get desc from object
$did = $jsonObject->{'did'};// Get id object
mysql_connect("localhost","root",""); // Conect to mysql, first parameter is location, second is mysql username and a third one is a mysql password
@mysql_select_db("findadeal") or die( "Unable to select database"); // Connect to database called test
$query = "UPDATE deal SET dname = {'$name'}, desc={'$desc'} WHERE dealid = {'$did'}";
$add = mysql_query($query);
$num = mysql_num_rows($add);
if($num != 0) {
echo "true";
} else {
echo "false";
}
?>
您需要使用反引號將MySQL中的保留字(例如desc
轉義
UPDATE deal
SET dname = {'$name'}, `desc`= {'$desc'} ....
^----^--------------------------here
您需要在更新后使用mysql_affected_rows()
而不是mysql_num_rows
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