在具有特定名稱的所有子目錄上運行python腳本

Question

我有一個帶一些參數的python腳本，我想在腳本所在的所有子目錄上運行此腳本。

我的想法是我想獲得腳本的自定義輸出，以將其保存在文件中。

這是我所做的：

for x in `find . -type d | grep data`;
do
python /full/path/to/file/script.py -f "%a
%t" $x/*.txt -o $x/res.txt
done

但這不起作用，我也不知道為什么。 for循環中的grep僅獲取包含.txt文件的目錄，並將腳本應用於這些目錄。

％a和％t之間的新行是因為我要自定義python腳本輸出的輸出，以在每2個變量之間包含一條新行

我究竟做錯了什么 ？

Answer 1

如果要從腳本所在的子目錄開始在所有子目錄上運行此腳本 ，請嘗試以這種方式進行操作：

import os

for path, directories, files in os.walk(os.path.dirname(os.path.realpath(__file__))):
    print path, directories, files
    txt_files = [arbitrary_file for arbitrary_file in files if arbitrary_file[-4:].lower() == ".txt"]

    #run your python here
    txt_files = [txt_file for arbitrary_file in files if arbitrary_file[]

如果您的原始代碼是這樣的：

import sys

text_files_to_process = #Do Something with sys.argv - or whatever you're using to parse your arguments.

with open("res.txt", "w") as f:
    #do something with all the text files, and write the output to res.txt.
    for text_file in text_files_to_process:
        with open(text_file) as tf:
            for line in tf:
                #whatever your text processing is
            tf.write("something")

那么您只需將其更改為如下所示：

import os

for path, directories, files in os.walk(os.path.dirname(os.path.realpath(__file__))):
    print path, directories, files
    txt_files = [arbitrary_file for arbitrary_file in files if arbitrary_file[-4:].lower() == ".txt"]

    txt_files = [txt_file for arbitrary_file in files if arbitrary_file[]

    with open("res.txt", "w") as f:
        #do something with all the text files, and write the output to res.txt.
        for text_file in txt_files:
            with open(text_file) as tf:
                for line in tf:
                    #whatever your text processing is
                tf.write("something")