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[英]Can't get method (getTest) to return true boolean method result if input matches a number in my array list
[英]Though my boolean method returns true or false correctly, I can't use the return in main
因此我的Boolean方法運行並返回正確的true或false。...但是我需要某種掃描程序函數才能將返回的內容放入if語句中。 這是我的主要代碼。 任何幫助表示贊賞! 另外,我的櫃台不起作用:(我是新來的。
import java.util.Random;
import java.util.Scanner;
public class CrapsP5 {
public static void main(String[] args) {
int number = 0, total, counter;
total = counter = 0;
String response;
Scanner console = new Scanner(System. in );
//1
System.out.println("Would you like to play craps? (Y/N)");
response = console.next();
if (response.equalsIgnoreCase("N")) {
System.exit(0);
}
//2
System.out.println("Welcome to craps. Would you like to see the rules? (Y/N)");
response = console.next();
if (response.equalsIgnoreCase("Y")) {
rules();
}
//3 call play method
play();
//I need something here to act like the scanner console does?? yes?? but what?
if (true) {
System.out.println("Congrats! You've won!");
counter++; //add 1 to win count (w)
total = counter;
play();
}
if (false) {
System.out.println("I'm sorry, you've lost.");
System.exit(0);
}
//4
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");
您的布爾方法是哪一種? 玩()? 如果是這樣的話
boolean result = play();
if(result){
...
}
else{
...
}
要么
if(play()){
...
} else {
...
}
嘗試:
if(play())
{
....
}
else
{
}
如果您的play()返回布爾值。
我想指出一點:
play();
if (true) {
System.out.println("Congrats! You've won!");
counter++; //add 1 to win count (w)
total = counter;
play();
}
表示,用戶第一次玩游戲,如果獲勝,流程進入條件塊,並再次進行玩游戲,無論用戶第二次玩游戲是贏還是輸,計數器都不會改變並且游戲通過執行以下操作結束:
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");
我建議使用while循環繼續播放,直到用戶迷路為止。 如:
while(play()){
System.out.println("Congrats! You've won!");
counter++;
total = counter;
}
//It is assumed that the counter and eventually the game should restart on losing
System.out.println("I'm sorry, you've lost.");
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");
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