[英]How to check if a string or multiple strings exists within an array in PHP
[英]how to check if a string exists in an array of strings
我將數據存儲在一個字符串中:例如$string='12';
'12'代表2個數據, 1
和2
在3列中,我存儲了相同的ID,數組如下:
ex1: $array= ('num1' => 1, 'num2' => 2, 'num3' => )
ex2: $array= ('num1' => 5, 'num2' => 4, 'num3' => 3)
如果兩個地方都存在數字,我怎么能比較這些並返回true?
例如:使用上面的例子:對於ex1: 12
將return TRUE
34
會return FALSE
為EX2: 345
會return TRUE
試試這個:你可以使用array_intersect ()。
$string = '12';
//split string into array of characters
$arr = str_split($string);
//testing columns
$compare1 = array('num1' => 1, 'num2' => 2, 'num3' => '');
$compare2 = array('num1' => 5, 'num2' => 4, 'num3' => 3);
//returns an array containing all the values of $arr inside $compare1
$int1 = array_intersect($arr, $compare1);
//returns an array containing all the values of $arr inside $compare2
$int2 = array_intersect($arr, $compare2);
//if $arr contents are in $compare1 return true, otherwise false
echo ! empty($int1);
//if $arr contents are in $compare2 return true, otherwise false
echo ! empty($int2);
嘗試in_array()函數http://php.net/manual/en/function.in-array.php
但我不明白為什么345會回歸真實
這有效,請看下面的結果:(兩個數組中的值必須存在才能返回true。
$result = true;
$string1 = '43';
$string = str_split($string1);
$example1 = array('num1' => 1, 'num2' => 2, 'num3' => 3, 'num4' => 4, 'num5' => 5);
$example2 = array('num1' => 5, 'num2' => 4, 'num3' => 3);
foreach ($string as $st) {
if((in_array($st, $example1) && in_array($st, $example2)) && $result == true){
$result = true; //true
} else {
$result = false;
}
}
if($result == true){
echo 1; //true
} else {
echo 0; //false
}
exit;
//Test Results:
//$string1 = '12'; //result 0
//$string1 = '34'; //result 1
//$string1 = '55'; //result 1
//$string1 = '43'; //result 1
我遲到了...但我已經開始,所以不妨! 這是我的解決方案:
function yayOrNay($array, $string) {
$stringArray = str_split($string);
$arrayDiff = array_diff($stringArray, array_values($array));
return empty($arrayDiff);
}
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