在Linux中使用systemd的啟動腳本

Question

我可以在下面執行此啟動服務，一旦運行就沒有錯誤顯示，但下面的服務器腳本不運行！

ln /lib/systemd/aquarium.service aquarium.service
systemctl daemon-reload
systemctl enable aquarium.service
systemctl start aquarium.service

謝謝

aquarium.service：

[Unit]
Description=Start aquarium server

[Service]
WorkingDirectory=/home/root/python/code/aquarium/
ExecStart=/bin/bash server.* start
KillMode=process

[Install]
WantedBy=multi-user.target

這是server.sh腳本

#!/bin/bash

PID=""

function get_pid {
   PID=`pidof python ./udpthread.py`
}

function stop {
   get_pid
   if [ -z $PID ]; then
      echo "server is not running."
      exit 1
   else
      echo -n "Stopping server.."
      kill -9 $PID
      sleep 1
      echo ".. Done."
   fi
}


function start {
   get_pid
   if [ -z $PID ]; then
      echo  "Starting server.."
      ./udpthread.py &
      get_pid
      echo "Done. PID=$PID"
   else
      echo "server is already running, PID=$PID"
   fi
}

function restart {
   echo  "Restarting server.."
   get_pid
   if [ -z $PID ]; then
      start
   else
      stop
      sleep 5
      start
   fi
}


function status {
   get_pid
   if [ -z  $PID ]; then
      echo "Server is not running."
      exit 1
   else
      echo "Server is running, PID=$PID"
   fi
}

case "$1" in
   start)
      start
   ;;
   stop)
      stop
   ;;
   restart)
      restart
   ;;
   status)
      status
   ;;
   *)
      echo "Usage: $0 {start|stop|restart|status}"
esac

Answer 1

嘗試使用“Type = forking”並使用完整的文件名。

[Unit]
Description=Start aquarium server

[Service]
WorkingDirectory=/home/root/python/code/aquarium/
Type=forking
ExecStart=/bin/bash server.sh start
KillMode=process

[Install]
WantedBy=multi-user.target

如果不起作用，請輸出此命令：

# journalctl -u aquarium.service