where子句中的多列查詢mysql

Question

從MySQL數據庫具有多個列的選擇框

以下代碼是zgr024的獲獎代碼

       <?php 
    include '../config.php';
    $sql = "SELECT * FROM megabase";  
    $resultaat = mysql_query($sql) or die (mysql_error());  
    $domains = array();
    while ($row = mysql_fetch_array($resultaat))       
    { 
       if (!empty($row['domeinnaam1'])) $domains[] = $row['domeinnaam1'];
       if (!empty($row['domeinnaam2'])) $domains[] = $row['domeinnaam2'];
    }
?>

   <select size="1" name="domeinnaam">
<?php
    foreach ($domains as $domain)
    {
        echo "<option>$domain</option>";
    } 
?>
    </select>

但是，此代碼在我有以下代碼的下一頁上導致了預期的錯誤。

    <?php 

     //MySQL Database Connect
     include 'config.php';

    $domeinnaam=$_POST['domeinnaam']; 

    $data = 'SELECT * FROM megabase WHERE domeinnaam = "'.$domeinnaam.'"'; 
      $query = mysql_query($data) or die("Couldn't execute query. ". mysql_error()); 
      $data2 = mysql_fetch_array($query); 


    ?> 

我如何更改最后一個代碼以與第一個代碼一起使用：

我努力了：

        <?php 

         //MySQL Database Connect
         include 'config.php';

        $domeinnaam=$_POST['domeinnaam'];
       $domeinnaamquerry='domeinnaam1'.'domeinnaam2'.'domeinnaam3'.'domeinnaam4'.'domeinnaam5'.'do meinnaam6'.'domeinnaam7'.'domeinnaam8'.'domeinnaam9'.'domeinnaam10';

        $data = 'SELECT * FROM megabase WHERE $domeinnaamquerry = "'.$domeinnaam.'"'; 
          $query = mysql_query($data) or die("Couldn't execute query. ".             mysql_error()); 
          $data2 = mysql_fetch_array($query); 


        ?> 

但是我收到以下錯誤：無法執行查詢。 “ where子句”中的未知列“ $ domeinnaamquerry”

Okey現在可以正常工作了，但是工作非常感謝大家的投入，這很有幫助。 並感謝您的警告。

這是代碼

     <?php 

      //MySQL Database Connect
      include 'config.php';

     $domeinnaam=$_POST['domeinnaam']; 

     $data = 'SELECT * FROM megabase WHERE domeinnaam1="'.$domeinnaam.'" OR domeinnaam2="'.$domeinnaam.'" OR domeinnaam3="'.$domeinnaam.'" OR domeinnaam4="'.$domeinnaam.'" OR domeinnaam5="'.$domeinnaam.'" OR domeinnaam6="'.$domeinnaam.'" OR domeinnaam7="'.$domeinnaam.'" OR domeinnaam8="'.$domeinnaam.'" OR domeinnaam9="'.$domeinnaam.'" OR domeinnaam10="'.$domeinnaam.'"    '; 
       $query = mysql_query($data) or die("Couldn't execute query. ". mysql_error()); 
       $data2 = mysql_fetch_array($query); 


     ?> 

Answer 1

嘗試

<?php 

    //MySQL Database Connect
    include 'config.php';

    $domeinnaam=$_POST['domeinnaam']; 

    $data = "SELECT * FROM megabase WHERE domeinnaam1 = '$domeinnaam' OR domeinnaam2 = '$domeinnaam' "; 
    $query = mysql_query($data) or die("Couldn't execute query. ". mysql_error()); 
    $data2 = mysql_fetch_array($query); 

?>

Answer 2

如果要將變量解釋為PHP中的值，則不能使用單引號。

$foo = 'World';

echo 'Hello $foo'; // Hello $foo
echo "Hello $foo"; // Hello World

因此，您想要

$data = "SELECT * FROM megabase WHERE $domeinnaamquerry = '".$domeinnaam."'"; 

盡管閱讀了此內容 ， 但了解了您為什么真的不想要那個。