php錯誤創建mysql表

Question

我有以下php文件來創建數據庫和表：

<?php
$slName = $_POST['slName'];
$con=mysqli_connect('localhost', 'setlist', 'music');
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

// Create database
$sql="CREATE DATABASE $slName";
if (mysqli_query($con,$sql))
  {
  echo "Database " . $slName . " created successfully";
  }
else
  {
  echo "Error creating database: " . mysqli_error();
  }


  // Create table
$tbl="CREATE TABLE main (name TEXT,orderno INT,Age TEXT)";

// Execute query
if (mysqli_query($con,$tbl))
  {
  echo "Table persons created successfully";
  }
else
  {
  echo "Error creating table: " . mysqli_error();
  }
?>

當它運行時我返回：

數據庫創建成功創建表時出錯：

我通過命令提示符成功執行了此操作：

CREATE TABLE main (name TEXT,orderno INT,Age TEXT);

我究竟做錯了什么？

非常感謝！

洛倫

Answer 1

您必須選擇要在其中創建表的數據庫

  mysqli_select_db($slName);

Answer 2

創建數據庫后添加mysqli_select_db($slName);