以隨機順序顯示CardLayout卡？

Question

我想以隨機順序在CardLayout中顯示卡片或屏幕。 我需要有關如何實現這一目標的指導。 我應該使用什么策略？

我嘗試使用下面的代碼，但它是按固定順序。 我希望能夠選擇我喜歡的訂單。

編輯！

抱歉，按隨機順序我並不是說改組。 但是，很高興知道。 我希望程序的用戶能夠輸入一些輸入。 根據輸入的值，顯示特定的屏幕/卡。

import java.awt.*;
import javax.swing.*;
import java.awt.event.*;

public class CardLayoutExample extends JFrame {

private int currentCard = 1;
private JPanel cardPanel;
private CardLayout cl;

public CardLayoutExample() {

    setTitle("Card Layout Example");
    setSize(300, 150);
    cardPanel = new JPanel();

    cl = new CardLayout();
    cardPanel.setLayout(cl);
    JPanel p1 = new JPanel();
    JPanel p2 = new JPanel();
    JPanel p3 = new JPanel();
    JPanel p4 = new JPanel();
    JLabel lab1 = new JLabel("Card1");
    JLabel lab2 = new JLabel("Card2");
    JLabel lab3 = new JLabel("Card3");
    JLabel lab4 = new JLabel("Card4");
    p1.add(lab1);
    p2.add(lab2);
    p3.add(lab3);
    p4.add(lab4);

    cardPanel.add(p1, "1");
    cardPanel.add(p2, "2");
    cardPanel.add(p3, "3");
    cardPanel.add(p4, "4");
    JPanel buttonPanel = new JPanel();
    JButton b1 = new JButton("Previous");
    JButton b2 = new JButton("Next");
    buttonPanel.add(b1);
    buttonPanel.add(b2);
    b1.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) {
            if (currentCard > 1) {
                currentCard -= 1;
                cl.show(cardPanel, "" + (currentCard));
            }
        }
    });

    b2.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) {
            if (currentCard < 4) {
                currentCard += 1;
                cl.show(cardPanel, "" + (currentCard));
            }
        }
    });
    getContentPane().add(cardPanel, BorderLayout.NORTH);
    getContentPane().add(buttonPanel, BorderLayout.SOUTH);
}

public static void main(String[] args) {
    CardLayoutExample cl = new CardLayoutExample();
    cl.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    cl.setVisible(true);
}
}

Answer 1

將CartLayouts放入List中，隨機播放List，按List順序添加到包含的布局。

Answer 2

這是直接跳轉到卡片的簡單方法。

final JButton jumpTo = new JButton("Jump To");
buttonPanel.add(jumpTo);
jumpTo.addActionListener( new ActionListener(){
    @Override
    public void actionPerformed(ActionEvent ae) {
        String[] names = {"1","2","3","4"};
        String s = (String)JOptionPane.showInputDialog(
            jumpTo,
            "Jump to card",
            "Navigate",
            JOptionPane.QUESTION_MESSAGE,
            null,
            names,
            names[0]);
        if (s!=null) {
            cl.show(cardPanel, s);
        }
    }
} );

顯然，這將需要對其余代碼進行一些更改。 這是一個SSCCE。

import java.awt.*;
import javax.swing.*;
import java.awt.event.*;

public class CardLayoutExample extends JFrame {

private int currentCard = 1;
private JPanel cardPanel;
private CardLayout cl;

public CardLayoutExample() {

    setTitle("Card Layout Example");
    setSize(300, 150);
    cardPanel = new JPanel();

    cl = new CardLayout();
    cardPanel.setLayout(cl);
    JPanel p1 = new JPanel();
    JPanel p2 = new JPanel();
    JPanel p3 = new JPanel();
    JPanel p4 = new JPanel();
    JLabel lab1 = new JLabel("Card1");
    JLabel lab2 = new JLabel("Card2");
    JLabel lab3 = new JLabel("Card3");
    JLabel lab4 = new JLabel("Card4");
    p1.add(lab1);
    p2.add(lab2);
    p3.add(lab3);
    p4.add(lab4);

    cardPanel.add(p1, "1");
    cardPanel.add(p2, "2");
    cardPanel.add(p3, "3");
    cardPanel.add(p4, "4");
    JPanel buttonPanel = new JPanel();
    JButton b1 = new JButton("Previous");
    JButton b2 = new JButton("Next");
    buttonPanel.add(b1);
    buttonPanel.add(b2);
    b1.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) {
            if (currentCard > 1) {
                currentCard -= 1;
                cl.show(cardPanel, "" + (currentCard));
            }
        }
    });

    b2.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) {
            if (currentCard < 4) {
                currentCard += 1;
                cl.show(cardPanel, "" + (currentCard));
            }
        }
    });

    final JButton jumpTo = new JButton("Jump To");
    buttonPanel.add(jumpTo);
    jumpTo.addActionListener( new ActionListener(){
        @Override
        public void actionPerformed(ActionEvent ae) {
            String[] names = {"1","2","3","4"};
            String s = (String)JOptionPane.showInputDialog(
                jumpTo,
                "Jump to card",
                "Navigate",
                JOptionPane.QUESTION_MESSAGE,
                null,
                names,
                names[0]);
            if (s!=null) {
                cl.show(cardPanel, s);
            }
        }
    } );

    getContentPane().add(cardPanel, BorderLayout.NORTH);
    getContentPane().add(buttonPanel, BorderLayout.SOUTH);
}

public static void main(String[] args) {
    CardLayoutExample cl = new CardLayoutExample();
    cl.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    cl.setVisible(true);
}
}

順便說一句-我的評論“您提示用戶輸入卡號的代碼部分在哪里？” 實際上是嘗試和交流的一種非常微妙的方法。 為了盡快獲得更好的幫助，請發布SSCCE 。