在while循環中顯示表

Question

我試圖在while循環中顯示一個表，每行有3行和3個td。 但我很困惑如何歸檔。

到目前為止這是我的代碼：

while($row = mysqli_fetch_array($result)){

    $testimonial    = $row['testimonial'];
  $cityName         = $row['city_name'];
  $name             = $row['name'];
  $imageName        = $row['image_name'];
  $member           = $row['membership_type'];
  $testimonial  = nl2br($testimonial);

    //Create new testimonial output
    $output  = "<table>\n";
    $output .= "  <tr>\n";
    $output .= "     <td>\n";
    $output .= "      <p>\n";
    $output .= "        <img src=\"".UPLOAD_DIR.$imageName."\" />";
    $output .= "         {$testimonial}";
    $output .= "      </p>\n";
    $output .= "     <p class=\"name\">{$name}<br />\n";
    $output .= "      <span>A Teacher - From {$cityName}</span></p>\n";
    $output .= "   </td>\n";
    $output .= "  </tr>\n";
    $output .= "</table>\n";

    echo $output;
}

上面的代碼給了我一個表，每行有多行和1個td。 但這不是我期待的結果。

任何人都可以告訴我如何在我的While loop顯示這樣的表格？

Answer 1

當前代碼為每個條目創建一個新表。 你想要的是將<table>和</table>塊移到循環之外，然后你想要一個計數器來跟蹤你處理過的單元數。 如果它是偶數，則啟動一個新的<tr> 。 否則，結束當前的</tr> 。 確保在最后檢查是否已完成</tr> ，並根據需要添加空<td></td> 。

Answer 2

嘗試這個

$i = 0;
echo "<table>\n<tr>";
while($row = mysqli_fetch_array($result)){
  $testimonial    = $row['testimonial'];
  $cityName         = $row['city_name'];
  $name             = $row['name'];
  $imageName        = $row['image_name'];
  $member           = $row['membership_type'];
  $testimonial  = nl2br($testimonial);
  //Create new testimonial output
  $output .= "     <td>\n";
  $output .= "      <p>\n";
  $output .= "        <img src=\"".UPLOAD_DIR.$imageName."\" />";
  $output .= "         {$testimonial}";
  $output .= "      </p>\n";
  $output .= "     <p class=\"name\">{$name}<br />\n";
  $output .= "      <span>A Teacher - From {$cityName}</span></p>\n";
  $output .= "   </td>\n";
  echo $output;
  if( $i %2 == 1 )
    echo "</tr><tr>\n";
  $i++;
}
echo "</tr>\n</table>\n";

---

編輯

通常，要在每行顯示n單元格，請將if語句更改為

if( $i % n == (n - 1) )

Answer 3

這要做到這一點

<?php

echo "<table>\n";

$cells = $total = 0;
$total_cells = mysqli_num_rows($result);

while($row = mysqli_fetch_array($result))
{
    $testimonial      = nl2br($row['testimonial']);
    $cityName         = $row['city_name'];
    $name             = $row['name'];
    $imageName        = $row['image_name'];
    $member           = $row['membership_type'];

    if ($cells === 0)
        echo "<tr>\n";

    //Create new testimonial output
    $output = "     <td>\n";
    $output .= "      <p>\n";
    $output .= "        <img src=\"".UPLOAD_DIR.$imageName."\" />";
    $output .= "         {$testimonial}";
    $output .= "      </p>\n";
    $output .= "     <p class=\"name\">{$name}<br />\n";
    $output .= "      <span>A Teacher - From {$cityName}</span></p>\n";
    $output .= "   </td>\n";

    echo $output;

    $cells++;
    $total++;       

    if ($cells === 3 || $total === $total_cells)
    {
        echo "</tr>\n";
        $cells = 0;
    }
}

echo "</table>\n";

?>